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syntax error!!


Pavlos1316

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Hi.. I have this code for check boxes

 

starting...

$home= 'unchecked';

.....

 

if (isset($_POST['Submit'])) {

if (isset($_POST['home'])) {

$home = $_POST['home'];

if ($home = = 'home') {

(line61)$home = 'checked';

}

}

}

 

when I submit I get:    syntax error, unexpected '=' in line 61

any advice?

 

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my connection string.... blabla.php

 

$dbhost = "localhost";
$dbname = "db";
$dbuser = "user";
$dbpass = "pass";

//Connect to database
mysql_connect ($dbhost, $dbuser, $dbpass)or die("Error: " .mysql_error());mysql_select_db($dbname) or die(mysql_error());

 

my form

 

<body>
<form id="form1" name="form1" method="post" action="blabla.php">
<span class="style3">
        <input type="checkbox" name="home" id="home" />	
<?PHP print $home; ?>
-</span>
</body>
</form>

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NO NOT REALLY...

 

I am new at this.. If I have an example I can read it and make it work for me...

 

But to create the example... no.. I have help from forums. This forum... :D

 

I ve learn how to use dreamweaver to desing my site and forms and buttons. it was pretty easy but I don't have the time to learn by my self how to write my own scripts.

 

So any help is welcomed...

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