preg_replace problems

[chris_rulez001]

what is wrong with this? when you post a message with swear words in it all it does is show the swear words.

 

code:

$message = $_POST['message'];
$R = "<font color=\"FF0000\">*Censored*</font>";
$notallowed = //array removed but all that is here is swear words
preg_replace($notallowed, $R, $message);

[samshel]

$notallowed = //array removed but all that is here is swear words

 

Is this an array? preg_match takes first parameter as a pattern

[chris_rulez001]

yes that is an array i took the array out because it had swear words in it

[samshel]

Try this:

 

$message = $_POST['message'];
$R = "<font color=\"FF0000\">*Censored*</font>";
$notallowed = //array removed but all that is here is swear words
for($i=0;$i<count($notallowed);$i++) {
   $message = preg_replace($notallowed, $R, $message);
}

[chris_rulez001]

awsome dude, it works

 

EDIT: thanks

[samshel]

Please mark the post as solved

[helraizer]

At the moment it's just an array, just a block of nothingness that isn't useful.

 

Basically, what I'm trying to say is you need to use foreach to break up the array.

 

<?php
$message = $_POST['message'];
$R = "<font color='#FF0000'>*Censored*</font>";
$notallowed = array("naughty word", "and another", "another");

foreach($notallowed AS $censor) {
if(preg_match("/$censor/i", $message) {
$message = preg_replace("/$censor/i", $R, $message);
  }
}
?>

 

Hope that helps,

Sam

 

EDIT: either this or Samshel's code'll suffice.

[chris_rulez001]

ok cheers both of you