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Hi,

I have a search form that contains 3 dropdown boxes:

- search_bedrooms
- search_price
- search_area

Each of these boxes contain values which will get info from a database when submitted, but they also have a value called [no preference], this is selected when the user doesn't want to search for any particular value.

When submitted it goes through to a page which has a MYSQL SELECT statement:

[code]$query = "SELECT * FROM property_details WHERE area = '$search_area' AND price = '$search_price' AND bedrooms = '$search_bedrooms'";[/code]

What I need to know is if the user selects [no preference] on any one of the dropdowns, how can I make the above SELECT statement not include that in the search, but still search on the other criterias.

(e.g. if in the search_bedrooms dropdown I selected [no preference], how could it be excluded from the search, but still include area and price?)

I know it can be achieved with multiple SELECT statements, but there has to be a more efficient way.

Hope that makes sense.

Many thanks in advance.
Mark
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I can provide you with pseudo code; my PHP skills are not the best:

- assign the first part of the query -- without any WHERE clause -- to one variable
- create a new array
- check to see if each of the 3 variable is equal to the "no preference value", and push on that specific condition to the above array if it is not
- if this array has length, prepend with " WHERE ", join with " AND ", and append to the original query variable

Hope that makes sense -- I'm not a PHP coder.
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