Parse error: syntax error, unexpected '=' in my script

colcar · June 9, 2008

Hi,

Can anyone help me I am receiving this error, when I try to load the script in my browser:

Parse error: syntax error, unexpected '=' in C:\Inetpub\wwwroot\newphoto.php on line 76

<?php
$db_host = 'localhost'; // don't forget to change 
$db_user = 'root'; 
$db_pwd = 'colum';
$database = 'colum';
$table = 'trailer';// use the same name as SQL table
$password = 'kinefad';// simple upload restriction,// to disallow uploading to everyone
if (!mysql_connect($db_host, $db_user, $db_pwd))    
die("Can't connect to database");
if (!mysql_select_db($database))    
die("Can't select database");
// This function makes usage of// $_GET, $_POST, etc... variables
// completly safe in SQL queries
function sql_safe($s){    
if (get_magic_quotes_gpc())        
	$s = stripslashes($s);    
return mysql_real_escape_string($s);
}
// If user pressed submit in one of the forms
if ($_SERVER['REQUEST_METHOD'] == 'POST'){   

if(isset($_POST['Submit']))  
{ 	//reads the name of the file the user submitted for uploading 

// cleaning title field    
//$title = trim(sql_safe($_POST['title']));  
$model = trim(sql_safe($_POST['model']));
$year = trim(sql_safe($_POST['year']));
$price = trim(sql_safe($_POST['price']));
$location = trim(sql_safe($_POST['location']));
$path = './images/';
$title = trim(sql_safe($_FILES['photo']['filename']));

if ($title == '') // if title is not set 

	$title = '(empty title)';// use (empty title) string    

if ($_POST['password'] != $password)  // cheking passwors        

	$msg = 'Error: wrong upload password';    

else    
{        
	if (isset($_FILES['photo']))        
	{                       
		if (!isset($msg)) // If there was no error            
		{                
			// Preparing data to be used in MySQL query                
			mysql_query("INSERT INTO {$table} SET 	

title='$title',model='$model',year='$year',price='$price',location='$location',path='$path'");                
			$msg = 'Success: image uploaded';            
		}        
	}        
elseif (isset($_GET['title']))      // isset(..title) needed     
	$msg = 'Error: file not loaded';
		// to make sure we've using                                            
		// upload form, not form                                            
		// for deletion           
if (isset($_POST['del'])) // If used selected some photo to delete        
{                         // in 'uploaded images form';            
	$id = intval($_POST['del']);            
	mysql_query("DELETE FROM {$table} WHERE id=$id");            
	$msg = 'Photo deleted';        
}    
}
}
?>
<html><head>
<title>Administration Page</title>
</head>
<body>
<?php
if (isset($msg)) // this is special section for                 
	// outputing message
{
?>
<p style="font-weight: bold;"><?php=$msg?>
<br>
<a href="<?php=$PHP_SELF?>">reload page</a>
<!-- I've added reloading link, because     
refreshing POST queries is not good idea -->
</p>
<?php
}
?>
<h1>Administration Page
</h1>
<h2>Uploaded images:</h2>
<form action="<?php=$PHP_SELF?>" method="post">
<!-- This form is used for image deletion -->

</form>
<h2>Upload new image:</h2>
<form action="<?php=$PHP_SELF?>" method="POST" enctype="multipart/form-data">
//<label for="title">Title:</label><br>
//<input type="text" name="title" id="title" size="64"><br><br>
<label for="model">Model:</label><br>
<input type="text" name="model" id="model" size="64"><br><br>
<label for="year">Year:</label><br>
<input type="text" name="year" id="year" size="64"><br><br>
<label for="price">Price:</label><br>
<input type="text" name="price" id="price" size="64"><br><br>
<label for="location">Location:</label><br>
<input type="text" name="location" id="location" size="64"><br><br>
<label for="photo">Photo:</label><br>
<input type="file" name="photo" id="filename"><br><br>
<label for="password">Password:</label><br>
<input type="password" name="password" id="password"><br><br>
<input type="submit" value="upload">
</form>
</body>
</html>

My code stopped working ever since I tried to extract the image name from an image that was posted. The code I added was:

	$title = trim(sql_safe($_FILES['photo']['filename']));

Any ideas on what I have done wrong or can anyone point me in the correct direction?

Thanks

jonsjava · June 9, 2008

quite a few errors. I think I fixed them all for you:

<?php
$db_host = 'localhost'; // don't forget to change 
$db_user = 'root'; 
$db_pwd = 'colum';
$database = 'colum';
$table = 'trailer';// use the same name as SQL table
$password = 'kinefad';// simple upload restriction,// to disallow uploading to everyone
if (!mysql_connect($db_host, $db_user, $db_pwd)) {   
die("Can't connect to database");
}
if (!mysql_select_db($database))  {  
die("Can't select database");
}
// This function makes usage of// $_GET, $_POST, etc... variables
// completly safe in SQL queries
function sql_safe($s){    
if (get_magic_quotes_gpc()) {       
	$s = stripslashes($s);    
return mysql_real_escape_string($s);
}
}
// If user pressed submit in one of the forms
if ($_SERVER['REQUEST_METHOD'] == 'POST'){   

if(isset($_POST['Submit']))  
{ 	//reads the name of the file the user submitted for uploading 

// cleaning title field    
//$title = trim(sql_safe($_POST['title']));  
$model = trim(sql_safe($_POST['model']));
$year = trim(sql_safe($_POST['year']));
$price = trim(sql_safe($_POST['price']));
$location = trim(sql_safe($_POST['location']));
$path = './images/';
$title = trim(sql_safe($_FILES['photo']['filename']));

if ($title == '') // if title is not set 

	$title = '(empty title)';// use (empty title) string    

if ($_POST['password'] != $password)  // cheking passwors        

	$msg = 'Error: wrong upload password';    

else    
{        
	if (isset($_FILES['photo']))        
	{                       
		if (!isset($msg)) // If there was no error            
		{                
			// Preparing data to be used in MySQL query                
			mysql_query("INSERT INTO {$table} SET 	

title='$title',model='$model',year='$year',price='$price',location='$location',path='$path'");                
			$msg = 'Success: image uploaded';            
		}        
	}        
elseif (isset($_GET['title']))      // isset(..title) needed     
	$msg = 'Error: file not loaded';
		// to make sure we've using                                            
		// upload form, not form                                            
		// for deletion           
if (isset($_POST['del'])) // If used selected some photo to delete        
{                         // in 'uploaded images form';            
	$id = intval($_POST['del']);            
	mysql_query("DELETE FROM {$table} WHERE id=$id");            
	$msg = 'Photo deleted';        
}    
}
}
?>
<html><head>
<title>Administration Page</title>
</head>
<body>
<?php
if (isset($msg)) // this is special section for                 
	// outputing message
{
?>
<p style="font-weight: bold;"><?php print $msg;?>
<br>
<a href="<?php print $_SERVER['PHP_SELF'];?>">reload page</a>
<!-- I've added reloading link, because     
refreshing POST queries is not good idea -->
</p>
<?php
}
}
?>
<h1>Administration Page
</h1>
<h2>Uploaded images:</h2>
<form action="<?php print $_SERVER['PHP_SELF'];?>" method="post">
<!-- This form is used for image deletion -->

</form>
<h2>Upload new image:</h2>
<form action="<?php print $_SERVER['PHP_SELF'];?>" method="POST" enctype="multipart/form-data">
//<label for="title">Title:</label><br>
//<input type="text" name="title" id="title" size="64"><br><br>
<label for="model">Model:</label><br>
<input type="text" name="model" id="model" size="64"><br><br>
<label for="year">Year:</label><br>
<input type="text" name="year" id="year" size="64"><br><br>
<label for="price">Price:</label><br>
<input type="text" name="price" id="price" size="64"><br><br>
<label for="location">Location:</label><br>
<input type="text" name="location" id="location" size="64"><br><br>
<label for="photo">Photo:</label><br>
<input type="file" name="photo" id="filename"><br><br>
<label for="password">Password:</label><br>
<input type="password" name="password" id="password"><br><br>
<input type="submit" value="upload">
</form>
</body>
</html>

revraz · June 9, 2008

Is this 76?

jonsjava · June 9, 2008

Line 76 (and a few after)

<?php
if (isset($msg)) // this is special section for                 
	// outputing message
{

<?php is all that's on line 76

thebadbad · June 9, 2008

Is this 76?

<p style="font-weight: bold;"><?php=$msg?>

Pretty close, yes (line 78). So to the OP, use "<?php echo $msg; ?>" instead of "<?php=$msg?>" to get rid of that particular error.

colcar · June 9, 2008

Hi,

Thanks for the help. That got rid of 3 further errors, but I am stuck on this error:

Parse error: syntax error, unexpected $end in C:\Inetpub\wwwroot\newphoto.php on line 113

Here is the updated code:

<?php
$db_host = 'localhost'; // don't forget to change 
$db_user = 'root'; 
$db_pwd = 'colum';
$database = 'colum';
$table = 'trailer';// use the same name as SQL table
$password = 'kinefad';// simple upload restriction,// to disallow uploading to everyone
if (!mysql_connect($db_host, $db_user, $db_pwd))    
die("Can't connect to database");
if (!mysql_select_db($database))    
die("Can't select database");
// This function makes usage of// $_GET, $_POST, etc... variables
// completly safe in SQL queries
function sql_safe($s){    
if (get_magic_quotes_gpc())        
	$s = stripslashes($s);    
return mysql_real_escape_string($s);
}
// If user pressed submit in one of the forms
if ($_SERVER['REQUEST_METHOD'] == 'POST'){   

if(isset($_POST['Submit']))  
{ 	//reads the name of the file the user submitted for uploading 

// cleaning title field    
//$title = trim(sql_safe($_POST['title']));  
$model = trim(sql_safe($_POST['model']));
$year = trim(sql_safe($_POST['year']));
$price = trim(sql_safe($_POST['price']));
$location = trim(sql_safe($_POST['location']));
$path = './images/';
$title = trim(sql_safe($_FILES['photo']['filename']));

if ($title == '') // if title is not set 

	$title = '(empty title)';// use (empty title) string    

if ($_POST['password'] != $password)  // cheking passwors        

	$msg = 'Error: wrong upload password';    

else    
{        
	if (isset($_FILES['photo']))        
	{                       
		if (!isset($msg)) // If there was no error            
		{                
			// Preparing data to be used in MySQL query                
			mysql_query("INSERT INTO {$table} SET 	

title='$title',model='$model',year='$year',price='$price',location='$location',path='$path'");                
			$msg = 'Success: image uploaded';            
		}        
	}        
elseif (isset($_GET['title']))      // isset(..title) needed     
	$msg = 'Error: file not loaded';
		// to make sure we've using                                            
		// upload form, not form                                            
		// for deletion           
if (isset($_POST['del'])) // If used selected some photo to delete        
{                         // in 'uploaded images form';            
	$id = intval($_POST['del']);            
	mysql_query("DELETE FROM {$table} WHERE id=$id");            
	$msg = 'Photo deleted';        
}    
}
}
?>
<html><head>
<title>Administration Page</title>
</head>
<body>
<?php
if (isset($msg)) // this is special section for                 
	// outputing message
{
?>
<p style="font-weight: bold;"><?php echo $msg; ?>
<br>
<a href="<?php echo $PHP_SELF; ?>">reload page</a>
<!-- I've added reloading link, because     
refreshing POST queries is not good idea -->
</p>
<?php
}
?>
<h1>Administration Page
</h1>
<h2>Uploaded images:</h2>
<form action="<?php echo $PHP_SELF; ?>" method="post">
<!-- This form is used for image deletion -->

</form>
<h2>Upload new image:</h2>
<form action="<?php echo $PHP_SELF; ?>" method="POST" enctype="multipart/form-data">
//<label for="title">Title:</label><br>
//<input type="text" name="title" id="title" size="64"><br><br>
<label for="model">Model:</label><br>
<input type="text" name="model" id="model" size="64"><br><br>
<label for="year">Year:</label><br>
<input type="text" name="year" id="year" size="64"><br><br>
<label for="price">Price:</label><br>
<input type="text" name="price" id="price" size="64"><br><br>
<label for="location">Location:</label><br>
<input type="text" name="location" id="location" size="64"><br><br>
<label for="photo">Photo:</label><br>
<input type="file" name="photo" id="filename"><br><br>
<label for="password">Password:</label><br>
<input type="password" name="password" id="password"><br><br>
<input type="submit" value="upload">
</form>
</body>
</html>

The line the error is refering to is the last line. This is odd. I also googled the error and it keeps pointing to using <?php instead of <? , but I have already done this.

Any ideas?

Thanks

kenrbnsn · June 9, 2008

An "unexpected end" error means that either you forgot to close a quoted string or your curly brackets "{ }" are unmatched.

Ken

darkfreaks · June 9, 2008

your brackets were left unmatched

<?php
$db_host = 'localhost'; // don't forget to change 
$db_user = 'root'; 
$db_pwd = 'colum';
$database = 'colum';
$table = 'trailer';// use the same name as SQL table
$password = 'kinefad';// simple upload restriction,// to disallow uploading to everyone
if (!mysql_connect($db_host, $db_user, $db_pwd))    
die("Can't connect to database");
if (!mysql_select_db($database))    
die("Can't select database");
// This function makes usage of// $_GET, $_POST, etc... variables
// completly safe in SQL queries
function sql_safe($s){    
if (get_magic_quotes_gpc())        
	$s = stripslashes($s);    
return mysql_real_escape_string($s);
}
// If user pressed submit in one of the forms
if ($_SERVER['REQUEST_METHOD'] == 'POST'){   

if(isset($_POST['Submit']))  
{ 	//reads the name of the file the user submitted for uploading 

// cleaning title field    
//$title = trim(sql_safe($_POST['title']));  
$model = trim(sql_safe($_POST['model']));
$year = trim(sql_safe($_POST['year']));
$price = trim(sql_safe($_POST['price']));
$location = trim(sql_safe($_POST['location']));
$path = './images/';
$title = trim(sql_safe($_FILES['photo']['filename']));

if ($title == '') // if title is not set 

	$title = '(empty title)';// use (empty title) string    

if ($_POST['password'] != $password)  // cheking passwors        

	$msg = 'Error: wrong upload password';    

else    
{        
	if (isset($_FILES['photo']))        
	{                       
		if (!isset($msg)) // If there was no error            
		{                
			// Preparing data to be used in MySQL query                
			mysql_query("INSERT INTO {$table} SET 	

title='$title',model='$model',year='$year',price='$price',location='$location',path='$path'");                
			$msg = 'Success: image uploaded';            
		}        
	}        
elseif (isset($_GET['title']))      // isset(..title) needed     
	$msg = 'Error: file not loaded';
		// to make sure we've using                                            
		// upload form, not form                                            
		// for deletion           
if (isset($_POST['del'])) // If used selected some photo to delete        
{                         // in 'uploaded images form';            
	$id = intval($_POST['del']);            
	mysql_query("DELETE FROM {$table} WHERE id=$id");            
	$msg = 'Photo deleted';        
}    
}
}
}

?>
<html><head>
<title>Administration Page</title>
</head>
<body>
<?php
if (isset($msg)) // this is special section for                 
	// outputing message
{
?>
<p style="font-weight: bold;"><?php echo $msg; ?>
<br>
<a href="<?php echo $PHP_SELF; ?>">reload page</a>
<!-- I've added reloading link, because     
refreshing POST queries is not good idea -->
</p>
<?php
}
?>
<h1>Administration Page
</h1>
<h2>Uploaded images:</h2>
<form action="<?php echo $PHP_SELF; ?>" method="post">
<!-- This form is used for image deletion -->

</form>
<h2>Upload new image:</h2>
<form action="<?php echo $PHP_SELF; ?>" method="POST" enctype="multipart/form-data">
//<label for="title">Title:</label><br>
//<input type="text" name="title" id="title" size="64"><br><br>
<label for="model">Model:</label><br>
<input type="text" name="model" id="model" size="64"><br><br>
<label for="year">Year:</label><br>
<input type="text" name="year" id="year" size="64"><br><br>
<label for="price">Price:</label><br>
<input type="text" name="price" id="price" size="64"><br><br>
<label for="location">Location:</label><br>
<input type="text" name="location" id="location" size="64"><br><br>
<label for="photo">Photo:</label><br>
<input type="file" name="photo" id="filename"><br><br>
<label for="password">Password:</label><br>
<input type="password" name="password" id="password"><br><br>
<input type="submit" value="upload">
</form>
</body>
</html>

colcar · June 10, 2008

Hi,

Thanks. I downloaded Notepad 2 and used it to match the brackets.....now the data won't upload to the DB....ahhhhhh

Also my upload messages i.e. successful upload or failed to upload aren't even appearing....it's just one thing after another

<?php
$db_host = 'localhost'; // don't forget to change 
$db_user = 'root'; 
$db_pwd = 'colum';
$database = 'colum';
$table = 'trex';// use the same name as SQL table
$password = 'kinefad';// simple upload restriction,// to disallow uploading to everyone
if (!mysql_connect($db_host, $db_user, $db_pwd))    
die("Can't connect to database");
if (!mysql_select_db($database))    
die("Can't select database");
// This function makes usage of// $_GET, $_POST, etc... variables
// completly safe in SQL queries
function sql_safe($s){    
if (get_magic_quotes_gpc())        
	$s = stripslashes($s);    
return mysql_real_escape_string($s);
}
// If user pressed submit in one of the forms
if ($_SERVER['REQUEST_METHOD'] == 'POST'){   

if(isset($_POST['submit']))  
{ 	//reads the name of the file the user submitted for uploading 

// cleaning title field    
$title = trim(sql_safe($_POST['name']));  
$model = trim(sql_safe($_POST['model']));
$year = trim(sql_safe($_POST['year']));
$price = trim(sql_safe($_POST['price']));
$location = trim(sql_safe($_POST['location']));
$path = './images/';
$imagename = trim(sql_safe($_FILES['photo']['filename']));

if ($title == '') // if title is not set 

	$title = '(empty title)';// use (empty title) string    

if ($_POST['password'] != $password)  // cheking passwors        

	$msg = 'Error: wrong upload password'; 

else    
{        
	if (isset($_FILES['photo']))        
	{                       
		if (!isset($msg)) // If there was no error            
		{                
			// Preparing data to be used in MySQL query                
			mysql_query("INSERT INTO {$table} SET 	

title='$title',model='$model',year='$year',price='$price',location='$location',path='$path',imagename='$imagename'");                
			$msg = 'Success: image uploaded';            
		}        
	}        
elseif (isset($_GET['name']))      // isset(..title) needed     
	$msg = 'Error: file not loaded';
		// to make sure we've using                                            
		// upload form, not form                                            
		// for deletion           
if (isset($_POST['del'])) // If used selected some photo to delete        
{                         // in 'uploaded images form';            
	$id = intval($_POST['del']);            
	mysql_query("DELETE FROM {$table} WHERE id=$id");            
	$msg = 'Photo deleted';        
}    
}
}
}
?>
<html><head>
<title>Administration Page</title>
</head>
<body>
<?php
if (isset($msg)) // this is special section for                 
	// outputing message
{
?>
<p style="font-weight: bold;"><? echo $msg; ?>
<br>
<a href="<?php echo $PHP_SELF; ?>">reload page</a>
<!-- I've added reloading link, because     
refreshing POST queries is not good idea -->
</p>
<?php
}
?>
<h1>Administration Page
</h1>
<h2>Uploaded images:</h2>
<form action="<?php echo $PHP_SELF; ?>" method="post">
<!-- This form is used for image deletion -->

</form>
<h2>Upload new image:</h2>
<form action="<?php echo $PHP_SELF; ?>" method="POST" enctype="multipart/form-data">
<label for="name">Name:</label><br>
<input type="text" name="name" id="name" size="64"><br><br>
<label for="model">Model:</label><br>
<input type="text" name="model" id="model" size="64"><br><br>
<label for="year">Year:</label><br>
<input type="text" name="year" id="year" size="64"><br><br>
<label for="price">Price:</label><br>
<input type="text" name="price" id="price" size="64"><br><br>
<label for="location">Location:</label><br>
<input type="text" name="location" id="location" size="64"><br><br>
<label for="photo">Photo:</label><br>
<input type="file" name="photo" id="filename"><br><br>
<label for="password">Password:</label><br>
<input type="password" name="password" id="password"><br><br>
<input type="submit" value="upload">
</form>
</body>
</html>

Any suggestions? I've been looking at it for hours and still can't figure it out.

Thanks

revraz · June 10, 2008

Use mysql_error after your queries and also echo your SQL to ensure all the variables are set.

colcar · June 10, 2008

Hi,

Thanks. I've located where the execution of the code gets to...not sure as to why it does not get any further.

It gets as far as the 1st help, but doesn't get to the 2nd one...Still trying to figure it out.

<p>help</p>
<?php

if(isset($_POST['submit']))  
{ 	//reads the name of the file the user submitted for uploading 

?>
<p>help2</p>
<?php
// cleaning title field    
$title = trim(sql_safe($_POST['name']));  
$model = trim(sql_safe($_POST['model']));
$year = trim(sql_safe($_POST['year']));

Thanks

revraz · June 10, 2008

Give your Input Submit a Name.

colcar · June 10, 2008

Hi,

Sorry forgot to mention that I gave the input and pressed submit. Still not showing help2 i.e. it's not entering the next if statement.

Thanks

revraz · June 10, 2008

That's because

if(isset($_POST['submit']))

is not set.

colcar · June 10, 2008

Hi,

It should be, see the code for the form\;

</form>
<h2>Upload new image:</h2>
<form action="<?php echo $_SERVER['PHP_SELF'];?>"  method="POST" enctype="multipart/form-data">
<label for="name">Name:</label><br>
<input type="text" name="name" id="name" size="64"><br><br>
<label for="model">Model:</label><br>
<input type="text" name="model" id="model" size="64"><br><br>
<label for="year">Year:</label><br>
<input type="text" name="year" id="year" size="64"><br><br>
<label for="price">Price:</label><br>
<input type="text" name="price" id="price" size="64"><br><br>
<label for="location">Location:</label><br>
<input type="text" name="location" id="location" size="64"><br><br>
<label for="photo">Photo:</label><br>
<input type="file" name="photo" id="filename"><br><br>
<label for="password">Password:</label><br>
<input type="password" name="password" id="password"><br><br>
<input type="submit" value="submit">
</form>
</body>
</html>

Thanks

revraz · June 10, 2008

I still dont see a NAME for your submit

Also, use this as your FORM tag

colcar · June 10, 2008

Hi,

Thanks a million that worked. It's updating the DB...

I found one more problem, could you help me?

I am trying to extract the name of the image from the one that is selected, it's not setting anthing in the DB.

Is this the correct way to extract it from the image?

$imagename = trim(sql_safe($_FILES['photo']['filename']));

Thanks

colcar · June 10, 2008

Hi,

I got it sorted eventually..thanks anyway.

Col

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Parse error: syntax error, unexpected '=' in my script

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