[SOLVED] debugging 1st php script - getting key of array

[kate_rose]

Hi,

 

I am trying to debug my first php script.  When I run it I get the following error

 

Parse error: syntax error, unexpected T_LNUMBER, expecting T_VARIABLE or '$' in C:\wamp\www\Guana_Plant_Key\test.php on line 52

 

I am running all of this on my pc on wampserver.

I tried looking up the error but I couldn't find an example that matched my situation.  I have included my script up until the error just for completeness.  It is getting stuck on the last line.  I am just trying to get the numerical index of the entry in the array being accessed.  Is "key" the wrong command.  I looked through the manual & couldn't find a good alternative but I may have missed it.

 

Kate

 

P.S.  Sorry for the excessive remarks - Since I am just learning it helps me keep track

 

<?php
// sets variables for opening guana_plants
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'guana_plant_db';

// connect to mysql to use guana_plants
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die('Error connecting to mysql');
mysql_select_db($dbname);

$seperator = " ~ ";							// define seperator
$picstorage = array();  					// make link or jpeg output-storage array
$scinamestorage = array(); 					// make scientific name storage array
$comnamestorage = array();					// make common name storage array
$comnamemysql = array ();					// make input from mysql common name array
$scinamemysql = array(); 					// make input from mysql scientific name array
$picmysql = array();						// make input from mysql link or jpeg storage array
$picexplode = array();						// make temp array for exploding

// load links or jpeg names from guana_plants db into $picmysql
$query = "SELECT flower_pics FROM guana_plants WHERE flower_pics <> 'none' AND flower_pics <> 'flower_pics'";
$result = mysql_query($query);
while ($row = mysql_fetch_array ($result, MYSQL_NUM)) {
$picmysql [] = $row [0];
}
// load scientific names from guana_plants db into $scinamemysql
$query = "SELECT Concat(genus, ' ', species) FROM guana_plants WHERE flower_pics <> 'none' AND flower_pics <> 'flower_pics'";
$result = mysql_query($query);
while ($row = mysql_fetch_array ($result, MYSQL_NUM)) {
$scinamemysql [] = $row [0];
}
// load common names from guana_plants db into $comnamemysql
$query = "SELECT common_names FROM guana_plants WHERE flower_pics <> 'none' AND flower_pics <> 'flower_pics'";
$result = mysql_query($query);
while ($row = mysql_fetch_array ($result, MYSQL_NUM)) {
$comnamemysql [] = $row [0];
}
foreach (picmysql as $pics); 					// begin to go through the array 1 entry at a time
if(strstr($pic,$seperator))  {					// If $pics contains the separator execute
$picexplode = array(); 							// Reset $picexplode to an empty array
$picexplode = explode(" ~ ", pics); 			// explode any string with a ~ into the picexplode array
$count = count ($picexplode); 					// count number of link or jpeg names in $picexplode
$countedlinks = $countedlinks + $count;	 		// add count of link or jpeg names to $counted variable so I will get # of links
$1key = key ($picmysql);						// load the location or key of the current link or jpeg name into $1key

[ohdang888]

put your code on this forum in the

 

/

 code brackets.... 
<?php
echo "It colors it so when can see whats wrong";
?>

[kenrbnsn]

A variable name can not start with a number.

 

Ken

[wildteen88]

The problem is you're starting a variable name with a number. Variable names can only begin with a letter or an underscore. You can use numbers afterwards.

$1key = key ($picmysql); // load the location or key of the current link or jpeg name into $1key

Change $1key to $key1 or $_1key

 

EDIT: Beaten to it.

[rhodesa]

also, you are missing several dollar signs on variables, and your foreach loop has a semi-colon at the end...should be like this:

 

foreach ($picmysql as $pics){                // begin to go through the array 1 entry at a time
  if(strstr($pic,$seperator))  {               // If $pics contains the separator execute
    $picexplode = array();                      // Reset $picexplode to an empty array
    $picexplode = explode(" ~ ", $pics);          // explode any string with a ~ into the picexplode array
    $count = count ($picexplode);                // count number of link or jpeg names in $picexplode
    $countedlinks = $countedlinks + $count;          // add count of link or jpeg names to $counted variable so I will get # of links
    $key = key ($picmysql);                  // load the location or key of the current link or jpeg name into $1key
  }
}

[kate_rose]

Wow that was amazingly fast  .  Thanks everybody for the help.

 

I guess this one is solved though I don't know how to put the green checkmark on it that indicates that.

 

I am sure I will be back for more.  Maybe even momentarily when I try to run this again.

 

Wild,

 

by the brackets I assume you mean the

<?php

?>

 

If so you needn't reply.

 

Thanks again

 

Kate

[wildteen88]

Wild,

 

by the brackets I assume you mean the

<?php

?>

I think you mean what ohdang888 said:

put your code on this forum in the

 

/

 code brackets.... 
<?php
echo "It colors it so when can see whats wrong";
?>

By that he/she meant to use

tags when posting code to the forum. It helps to make code more readable and separates the code form what you're saying (text).  I edited you post earlier and added the code tags.

 

To mark topic solved, the button is in the menu at the bottom of page (before the quick reply box).