[SOLVED] I need help with displaying images!

[vetman]

I can display images in a table but in a coulmn only. I need help making the table of 3 columns across and 2 rows down before pagination. Here is part of my existing code in which I use Highslide and pagination. Any help would be appreciated!

Thanks in advance!

 

<?php


// store the record of the "gold" table into $row

$current = '';


// keeps getting the next row until there are no more to get

while($row = mysql_fetch_array( $result ))
	 {
$id = $row['id'];
if (!$current) {
echo "<center><table>";
$current = $id;
} elseif ($current != $id){
echo "</table><br><br><table>";
$current = $id;
}
// Print out the contents of each row into a table
echo '<tr>
                           <td><div><a id="thumb1" href="'.$row['image'].'" class="highslide" onclick="return hs.expand(this)">
	<img src="'.$row['image_th'].'" title="Click to enlarge" /></a>

<div class="highslide-caption">'.$row['caption'].'
</div></td>';

}
        echo "</table>";
        echo "<br>";
        
?>

[MadTechie]

Untested but try this

<?php
// store the record of the "gold" table into $row

$current = '';


// keeps getting the next row until there are no more to get
$SetRows = 3;
$RowCount = 0;
while($row = mysql_fetch_array( $result ))
{
	$id = $row['id'];
	if (!$current) {
		echo "<center><table>";
		$current = $id;
	} elseif ($current != $id){
		echo "</table><br><br><table>";
		$current = $id;
	}
	echo ($RowCount==0)?'<tr>':'';
	echo '<td><div><a id="thumb1" href="'.$row['image'].'" class="highslide" onclick="return hs.expand(this)"><img src="'.$row['image_th'].'" title="Click to enlarge" /></a><div class="highslide-caption">'.$row['caption'].'</div></td>';
	echo ($RowCount==$SetRows)?'</tr>':'';
	$RowCount = ($RowCount==0)?$SetRows)?:$RowCount--;
}
echo ($RowCount!=$SetRows)?'</tr>':'';
        echo "</table>";
        echo "<br>";
        
?>

[vetman]

I'm getting an error: Parse error: parse error, unexpected ')'

Because I added it to my code, I can't tell the line number.

[vetman]

Anyone!

[hitman6003]

Pretty sure it has to do with this line:

 

$RowCount = ($RowCount==0)?$SetRows)?:$RowCount--;

[vetman]

That's the line I thought it was also. I tried several combinations but to no avail.

[hitman6003]

Without really checking to see what your code is trying to do, try this:

 

$RowCount = ($RowCount == 0 ? $SetRows : $RowCount--);

[vetman]

Well, the error went away, but the page didn't change, it came up as it has always done. What I'm trying to do is post 3 picture across the screen in 2 different rows for a total of six pictures per page.

[MadTechie]

Opps, revised, i didn't notice the creation of the table in the loop

 

try this

<?php
// store the record of the "gold" table into $row

$current = '';

// keeps getting the next row until there are no more to get
$SetRows = 3;
$RowCount = 0;
echo "<center><table>\n";
while($row = mysql_fetch_array( $result ))
{
	$id = $row['id'];
	echo ($RowCount==0)?'<tr>':'';
	echo '<td><div><a id="thumb1" href="'.$row['image'].'" class="highslide" onclick="return hs.expand(this)"><img src="'.$row['image_th'].'" title="Click to enlarge" /></a><div class="highslide-caption">'.$row['caption'].'</div></td>'."\n";
	echo ($RowCount==$SetRows)?"</tr>\n":'';
	$RowCount = ($RowCount==0)?$SetRows:$RowCount-1;
}
echo ($RowCount!=$SetRows)?"</tr>\n":"";
    echo "</table></center>";
    echo "<br>";
        
?>

[vetman]

Thanks, I really appreciate you help! Works fine now! I just couldn't figure it out.