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ok so i am fairly new to both PHP and MySQL and I am trying to learn the basics. I created a rating application everything so far works but now i would like to make a top 10. I have a table ('ratings') with rows:
id (the id for each rating from each user)
article (which page the rating is for)
rate (the actuall rating)
ip (the ip address of the rate-or)

i am trying to basically query the rows "article" and "rate"
then create a top ten list where the articles are grouped together and the rates for each article are averaged and then ordered desc. i got this far:

$result = mysql_query("SELECT article, rate FROM ratings order by rate desc");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}

$row = mysql_fetch_row($result);
echo "Row 0:", $row[0];
echo "Row 1:", $row[1];
echo "Row 2:", $row[2];
echo "Row 3:", $row[3];
echo "Row 4:", $row[4];
echo "Row 5:", $row[5];

i dont think i am even close to what i am trying to do....any ideas?

any help will be greatly apperciated!


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https://forums.phpfreaks.com/topic/11099-help-with-mysql-queries/
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[!--quoteo(post=379751:date=Jun 3 2006, 06:36 PM:name=fenway)--][div class=\'quotetop\']QUOTE(fenway @ Jun 3 2006, 06:36 PM) [snapback]379751[/snapback][/div][div class=\'quotemain\'][!--quotec--]
Sounds like you want something like the following (UNTESTED):

[code]SELECT article, AVG(rate) FROM ratings GROUP BY id ORDER BY rate DESC LIMIT 10[/code]
[/quote]

that does point me in the right direction but i am still having trouble echo-ing and displaying the result in an organized list (aka) instead of Article integer an html tag to represent a link to another page
[!--quoteo(post=379962:date=Jun 4 2006, 01:32 PM:name=theadmininator)--][div class=\'quotetop\']QUOTE(theadmininator @ Jun 4 2006, 01:32 PM) [snapback]379962[/snapback][/div][div class=\'quotemain\'][!--quotec--]
yes i started to figure that out last night having a link rather than a article number
but the main thing is out how do i group the articles together and average the votes to round to the nearest .5
[/quote]
Well, the query above is already grouping/averaging -- you can always call the ROUND() function if you desire.
actually i figured out how to group the articles and average them but i would like the article ID number to represent an hyper link with representitive text aka instead of it outputing

Article: 101
Avg Rating: 9.5

i need it to look like

[a href=\"http://testlink.html\" target=\"_blank\"]file name[/a]
Avg Rating: 9.5

------------------
so far i have:

$result = mysql_query("SELECT article, AVG(rate) FROM ratings GROUP BY article ORDER BY rate DESC LIMIT 10");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}

while ($row = mysql_fetch_array($result, MYSQL_NUM)) {

printf("<b>Article:</b> %s<br><b>Avg Rate:</b> %s<br><br><hr>", $row[0], $row[1]);

}

mysql_free_result($result);



any ideas?
I'm not sure I know what you mean -- first, you should be grouping by ID. Second, if you return this ID in your column list, you can compose whatever URL you desire. I don't see how I can be of any more help -- please clarify. [!--sizeo:2--][span style=\"font-size:10pt;line-height:100%\"][!--/sizeo--][i]BTW, I'll be gone for the rest of the day.[/i][!--sizec--][/span][!--/sizec--]
[!--quoteo(post=380006:date=Jun 4 2006, 03:29 PM:name=fenway)--][div class=\'quotetop\']QUOTE(fenway @ Jun 4 2006, 03:29 PM) [snapback]380006[/snapback][/div][div class=\'quotemain\'][!--quotec--]
I'm not sure I know what you mean -- first, you should be grouping by ID. Second, if you return this ID in your column list, you can compose whatever URL you desire. I don't see how I can be of any more help -- please clarify. [!--sizeo:2--][span style=\"font-size:10pt;line-height:100%\"][!--/sizeo--][i]BTW, I'll be gone for the rest of the day.[/i][!--sizec--][/span][!--/sizec--]
[/quote]

i am pretty sure i do want to group by article becuase i dont even call the data from the row id i only want the each articles average score. how ever all i am trying to do is convert the article which is an integer to a link to the article (article.php)

so far i get an array from $row[0] of all the article numbers grouped with $row[1] thier average rating.

i've been trying something like:

while ($row = mysql_fetch_array($result, MYSQL_NUM)) {

$article = $row[0];

//adding this if statement

[b]if ($article = '100' ) {
// code here run if $var is positive
$article = '<a href="article.php">The Full House</a>';[/b]
}

printf("<b>Article:</b> %s<br><b>Avg Rate:</b> %s<br><br><hr>", $article, $row[1]);

}

but it displays the link for all articles not just the article 100

thanks for all your help so far...
[!--quoteo(post=380263:date=Jun 5 2006, 01:08 PM:name=fenway)--][div class=\'quotetop\']QUOTE(fenway @ Jun 5 2006, 01:08 PM) [snapback]380263[/snapback][/div][div class=\'quotemain\'][!--quotec--]
Oh... article is your UID. Why not do the following?

[code]if ($article = '100' ) {
// code here run if $var is positive
$article = '<a href="article.php?uid=$article">The Full House</a>';
}[/code]
[/quote]



i did try that. it out puts every Article (UID) as the link not just the ones that are 100

would it work if i called all the other numbers as else if statements? if so how to i structer that?
thanks soooooo much
thats crazy i was sooo close the whole time.
ps. i have been working on this script straight for about 4 days.

on last question...

on my original rating script i have set it so that an ip address can only vote 1 time. but i think i did it wrong becuase i want it to be able to only rate each article one time and i can't vote on any other articles in the same ip heres the code so far:

on the article page it requires this file and calls fuction show form in the page.

[code]

$days     = 0;
$m        = 2;
$C        = 6;

@mysql_connect($server,$username,$password);
@mysql_select_db($database);

if($_POST['action'] == "doit")
{
  if($_POST['rates']>0 && $_POST['rates']<11 && !empty($_POST['rateit_id']))
  {

//get the users IP

   $ip  = getenv("REMOTE_ADDR");

//this query is the one i am wondering about

   $query = "SELECT count(*) AS num FROM ratings WHERE (datum>SUBDATE(CURRENT_DATE(),INTERVAL ".$GLOBALS['days']." DAY) AND ip='$ip' AND article='".$_POST['rateit_id']."')";

   $rs = mysql_query($query) or die("LINE 17:".mysql_error());
   $as = mysql_fetch_array($rs);
   if($as[num]==0)

//here is where it posts the ip and other info into the database

      mysql_query("INSERT INTO ratings VALUES(0,'".$_POST['rateit_id']."','".$_POST['rates']."','".$ip."',NOW())") or die(mysql_error());
   echo $ad[num];
  }
}

function ShowForm($id,$num,$rate_me="Rate Me",$rate_it="Rate!",$class="")
{
   echo '<form action="'.$GLOBALS['PHP_SELF'].'" method="post">';
   echo '<select name="rates" class="'.$class.'">';
   echo '<option value="x" selected>'.$rate_me.'</option>';
   for($x=$num;$x>0;$x--)
    echo '<option value="'.$x.'">'.$x.'</option>';
   echo '</select>';
   echo '<input type="hidden" name="rateit_id" value="'.$id.'">';
   echo '<input type="hidden" name="action" value="doit"> ';
   echo '&nbsp;<input type="submit" value="'.$rate_it.'" class="'.$class.'">';
   echo '</form>';
}[/code]
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