[SOLVED] IE wont display PHP on a page

mark110384 · June 20, 2008

A bit of a strange one, I've been developing some code for a shopping cart, it works fine in FireFox bit when I tried it in IE one of the pages didn't work, it is as though the PHP isn't even there or the HTML table that contains the PHP for that matter. Could anyone shed any light on this problem?

Jabop · June 20, 2008

This has nothing to do with IE. Double check what you're doing.

jonsjava · June 20, 2008

well, that doesn't sound like a PHP issue, it sounds like a browser issue. If you post your code, we could tell you more reliably if the issue is browser or script.

mark110384 · June 20, 2008

<?

/*#############################################################

- Script Name: addcart.php -

- Description: Add a selected item to the table cart_items, -

- check if it already exist and update and insert accordingly -

#############################################################*/

session_start();

$session = session_id();

session_register($session);

//Get values from itemdesc.php

$qty = $_POST["qty"];

$itemname = $_POST["itemName"];

$price = $_POST["price"];

$itemid = $_POST["itemId"];

$createdate = date("Y-m-d G:i:s");

?>

<tr>

<td><font face = "Arial" size ="4"><? echo $itemname; ?> was added to your shopping trolley.</font></td>

</tr>

</table>

<?

include("function.php");

//Get a connection to the database

$connect = @ConnectToDb($dbhost, $dbuser, $dbname);

//Update the session timestamp

$updatesession = @UpdateSessionDate($newdate, $session);

//Find itemId sent via viewitems.php addtotrolley button

$sqlfinditem = "SELECT * FROM items WHERE itemId = '$itemid'";

$queryresult = mysql_query($sqlfinditem);

while($myrow = mysql_fetch_array($queryresult))

{

$itemname = $myrow['itemName'];

$itemdesc = $myrow['itemDesc'];

$price = $myrow['price'];

$imagepath = $myrow['imagePath'];

$alt = $myrow['alt'];

//Set Quantity to = 1 if quantity string is empty otherwise preceed

if (!$qty)

{

$quant = 1;

}

else

{

$quant = $qty;

}

//Search to see if the itemId already exist within cart_items

$sqlselect = "SELECT * FROM cart_items WHERE itemId = '$itemid' and session = '$session'";

$result = mysql_query($sqlselect);

$itemcount = mysql_num_rows($result);

$itmid = "";

$itmid = $myrow['itemId'];

//Count the number of rows found and less than or = to 0 insert in cart

if ($itemcount <= 0)

{

//$qty =mysql_real_escape_string($qty);

$sqlinsert= "INSERT INTO cart_items (itemId, price, quantity, session, createdate) values ('$itemid', '$price','$quant', '$session', '$createdate')";

if (mysql_query($sqlinsert))

{

?>

<tr>

<tr>

<td><? echo "<font face= Arial size = 2><b>£</b>" ."<b>$price /Each</b><br></font>";?></td>

</tr>

<tr>

<td><? echo "<font face=Arial size = 2><b>$itemid $itemname</b></font>";?></td>

</tr>

<tr>

</tr>

</table></td>

</tr>

</table>

<?

}

else

{

echo "Error! Failed to add item to cart.";

}

else

{

$quantity ="";

while($myrow = mysql_fetch_array($result))

{

$quantity = $myrow['quantity'];

}

$totalqty = $quantity + $quant;

// Else if itemid exists in cart_items update with new data

mysql_query ("UPDATE cart_items SET quantity = '$totalqty' WHERE itemId = '$itemid' and session = '$session'");

?>

<tr>

<tr>

<td><? echo "<font face= Arial size = 2><b>£</b>" ."<b>$price /Each</b><br></font>";?></td>

</tr>

<tr>

<td><? echo "<font face=Arial size = 2><b>$itemid $itemname</b></font>";?></td>

</tr>

<tr>

</tr>

</table></td>

</tr>

</table>

<?

}

//}

?>

<html>

<head>

</head>

<title>Lilley and Gillie - <? echo "$itemname successfully added to your shopping trolley";?></title>

<body>

<tr>

</tr>

<tr>

</tr>

</table>

</body>

<?

}

?>

</html>

lemmin · June 20, 2008

If you view source on the page in IE does it give you anything? if so, can you post that?

mark110384 · June 23, 2008

Yeah this is the source code from IE

<table width = "800" border = "0" cellpadding="0" cellspacing ="0" bgcolor="#0099CC" align="center">
<tr>

<td><font face = "Arial" size ="4"> was added to your shopping trolley.</font></td>

</tr>

</table>

</body>

</html>

And the following in Firefox

<table width = "800" border = "0" cellpadding="0" cellspacing ="0" bgcolor="#0099CC" align="center">
<tr>

<td><font face = "Arial" size ="4"> was added to your shopping trolley.</font></td>

</tr>

</table>

<table width="671" border="0" cellspacing="0" cellpadding="0">

<tr>

<td width="339"></td>

<td width="393"><table width="393" border="0" cellspacing="0" cellpadding="0">

<tr><td width="100"><img src = 'F0750.JPG' alt = 'Set Square Image' height = 200 width = 200 border = 0/></td>

<td width="217"><table width="227" border="0" cellspacing="0" cellpadding="0">

<tr>

<td><font face= Arial size = 2><b>£</b><b>2.99 /Each</b><br></font></td>

</tr>

<tr>

<td><font face=Arial size = 2><b>F0750 Set Square</b></font></td>

</tr>

<tr>

<td height ="150"></td>

</tr>

</table></td>

</tr>

</table>

<html>

<head>

</head>

<title>Lilley and Gillie - Set Square successfully added to your shopping trolley</title>

<body>

<table width="350" border="0" cellspacing="0" cellpadding="0">

<tr>

<td height="60"></td>

<td></td>

</tr>

<tr>

<td height="38"><a href="viewitems.php"><img src = "continueshopping.bmp" border = "0"/></a></td>

<td><a href="cart.php"><img src = "viewcartbutton.bmp" border = "0"/></a></td>

</tr>

</table>

</body>

</html>

mark110384 · June 23, 2008

The following is coding for the button passing the itemid over if its any help

<? echo "<input type='image' src='addtotrolley.bmp' border='0' alt='Add' value = '$itemid' name = 'itemId'/>";?>

mark110384 · June 23, 2008

I think that it is a problem that IE does not send the value from the button, has anyone else experineced this problem?

trq · June 23, 2008

The following is coding for the button passing the itemid over if its any help

<? echo "<input type='image' src='addtotrolley.bmp' border='0' alt='Add' value = '$itemid' name = 'itemId'/>";?>

Thats isn't valid php.

<?php echo "<input type='image' src='addtotrolley.bmp' border='0' alt='Add' value = '$itemid' name = 'itemId'/>"; ?>

mark110384 · June 23, 2008

The following is coding for the button passing the itemid over if its any help

Quote

<? echo "<input type='image' src='addtotrolley.bmp' border='0' alt='Add' value = '$itemid' name = 'itemId'/>";?>

Thats isn't valid php.

<?php echo "<input type='image' src='addtotrolley.bmp' border='0' alt='Add' value = '$itemid' name = 'itemId'/>"; ?>

???

mark110384 · June 23, 2008

Found a soloution, I've put a hidden field containing the value that I want to pass

mark110384 · June 23, 2008

Unfortunately that only adds the last item to the cart and not the one user selects, back to the drawing board

mark110384 · June 23, 2008

I just changed the button to

echo "<a href='addcart.php?item_selected=$itemid'><img src = 'addtotrolley.bmp' border = '0'/></a>"

and it appears to work in both browsers with a couple of modifications to the addcart.php code

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[SOLVED] IE wont display PHP on a page

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