[SOLVED] Unexpected ')' help

[GreenUser]

Hi all!

 

I am a little lost why I receive these error's, am working from a book.  Of course, the page doesn't display. 

 

PHP Parse error:  syntax error, unexpected ')' in C:\\Program Files\\Apache\\htdocs\\news\\viewstory.php on line 38

 

When I comment out that line, line 49 has an unexpected ')' as well. 

 

<?php

require("config.php");
require("functions.php");

if(pf_check_number($_GET['id']) == TRUE) {
$validid = $_GET['id'];
}
else {
header("Location: " . config_basedir . "/index.php");
}

require("header.php");

$sql = "SELECT * FROM stories WHERE id = " . $validid . ";";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);

echo "<h1>" . $row['subject'] . "</h1>";
echo date("D jS F Y g:i A", strtotime($row['dateposted'])) . "<br />";
echo nl2br($row['body']);

$avgsql = "SELECT COUNT(id) AS number, AVG(rating) AS avg FROM ratings WHERE story_id = " . $validid . ";";
$avgresult = mysql_query($avgsql);
$avgrow = mysql_fetch_assoc($avgresult);

echo "<p>";
echo "<strong>Rating</strong> ";

if($avgrow['number'] == 0) {
echo "No Ratings!";
}

else {
$a = (round($avgrow['avg'] * 2) / 2) . "<br>";
$a *= 10;
}
if($a%5 == 0 && $a%10 != ) {                   /// line 38
	$range = ($a / 10) - 0.5;
}
else {
	$range = $a / 10;
}

for($i=1;$i<=$range;$i++) {
echo "<img src='" . $config_basedir . "img/full.gif'>";
}

if($a%5 == 0 && $a%10 != ) {
echo "<img src='" . $config_basedir . "img/half.gif'>";
}

$a = $a / 10;
$remain = 10 - $a;

for($r=1;$r<=$remain;$r++) {
	echo "<img src='" . $config_basedir . "img/none.gif'>";
	}

	{
	echo "<br />";

	echo "<strong>Rate this story</strong>: ";

	if($_SESSION['SESS_USERNAME']) {
		for($i=1;$i<=10;$i++) {
			echo "<a href='ratestroy.php?id=" . $validid . "&rating=" . $i . "'>" . $i . "</a> ";
		}
	}
	else {
		echo "To vote, please <a href='userlogin.php'>log in</a>.";
	}

echo "</p>";
require("footer.php");

?>

 

Thank you

[Stephen]

<?php

require("config.php");
require("functions.php");

if(pf_check_number($_GET['id']) == TRUE) {
$validid = $_GET['id'];
}
else {
header("Location: " . config_basedir . "/index.php");
}

require("header.php");

$sql = "SELECT * FROM stories WHERE id = " . $validid . ";";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);

echo "<h1>" . $row['subject'] . "</h1>";
echo date("D jS F Y g:i A", strtotime($row['dateposted'])) . "<br />";
echo nl2br($row['body']);

$avgsql = "SELECT COUNT(id) AS number, AVG(rating) AS avg FROM ratings WHERE story_id = " . $validid . ";";
$avgresult = mysql_query($avgsql);
$avgrow = mysql_fetch_assoc($avgresult);

echo "<p>";
echo "<strong>Rating</strong> ";

if($avgrow['number'] == 0) {
echo "No Ratings!";
}

else {
$a = (round($avgrow['avg'] * 2) / 2) . "<br>";
$a *= 10;
}
if($a%5 == 0 && $a%10 != null) {                   /// line 38
	$range = ($a / 10) - 0.5;
}
else {
	$range = $a / 10;
}

for($i=1;$i<=$range;$i++) {
echo "<img src='" . $config_basedir . "img/full.gif'>";
}

if($a%5 == 0 && $a%10 != null ) {
echo "<img src='" . $config_basedir . "img/half.gif'>";
}

$a = $a / 10;
$remain = 10 - $a;

for($r=1;$r<=$remain;$r++) {
	echo "<img src='" . $config_basedir . "img/none.gif'>";
	}

	{
	echo "<br />";

	echo "<strong>Rate this story</strong>: ";

	if($_SESSION['SESS_USERNAME']) {
		for($i=1;$i<=10;$i++) {
			echo "<a href='ratestroy.php?id=" . $validid . "&rating=" . $i . "'>" . $i . "</a> ";
		}
	}
	else {
		echo "To vote, please <a href='userlogin.php'>log in</a>.";
	}

echo "</p>";
require("footer.php");

?>

 

Try that now. I added null to the last bit.

[kenrbnsn]

Both line 38 and line 49 are the same

<?php
if($a%5 == 0 && $a%10 != )
?>

 

They are both missing something after the "!=" and before the ")".

 

Ken

[GreenUser]

Ah, thank you very much Stephan and Ken.

 

Stephan that worked great after I added a } I forgot to at the end.

 

What does the null do in that statement?

[Stephen]

null is nothing, but you were just doing "!= " to check for that I believe.

[GreenUser]

Ah, I see.  Thank you.