if statement not working

[onedumbcoder]

i am trying to see if an element exist in result, if not print out br, but it is not doing that

 

if(!$emptyList && $counterX > 0)
{
right();
$loop++;

if($tracker)
{
	if(isset($result))
	{
		$List = mysql_fetch_array($result);
	}
	else
	{
		$emptyList = true;
	}
}
}
else
{
echo "<br>";
}

 

 

here result has only one element so after the first time it runs, it should go to emptylist = true, but that is not happening it is going to $list = mysql_fetch_array($result)

 

can someone help me.

 

ps

 

the number of rows affected was 1, so i know for sure there is only one element.

[strayduck]

I think you need to specify a condition for isset($result), i.e.

 

if (isset($result) == 1)

 

or

 

if (isset($result) != 0)

[BloodyMind]

can u explain more ?

and btw

I see $result is always true

u can say

<?php
if ($numrows > 0) {
// do this
}else {
// do something else
}
?>

[strayduck]

I think you may have answered your own question!

 

Yes, I think $result will always be true even if it returns no answers.

 

Using the number of rows as a result is probably a better way of doing it, as you can use the code that you posted.