[SOLVED] PHP code in a string variable?

[kalevra]

Is there a way to make something like this work?

 

$count = 3;

$string = "

for ($i=1; $i<$count; $i++){

echo \"This is line number $i\"\n\;

}

";

 

echo $string;

 

I'd like it to echo:

This is line number 1

This is line number 2

This is line number 3

 

But it echoes the "un-processed" php code instead...

 

 

 

[kenrbnsn]

If you're getting unprocessed PHP output, your webserver may not support PHP at all. The code you gave is full of syntax errors.

 

The following code will work:

<?php
$count = 3;
for ($i=1; $i <= $count; $i++)
     echo "This is line number $i<br>\n";
?>

 

Ken

[Bendude14]

<?php
$count = 4;
$string = "";
for($i=1; $i < $count; $i++){

echo "This is line number $i"."<br />";
}

?>

 

Try this

[Lodius2000]

im going with ken but i think he forgot some curly braces

<?php
$count = 3;
for ($i=1; $i <= $count; $i++){
     echo "This is line number $i<br>\n";
}
?>

 

correct me if im wrong ken, but i think that will do it

[kalevra]

Ken's solution does work...

But I need the code to be in a string and echo that string.

 

Not simply doing a loop to echo the lines.

[Bendude14]

Ok well they are both the same apart from mine was only < (smaller than) and Ken's one <= (smaller than or equal to)

 

 

Ken's code works without the curly brackets but feel free to add them it will still work

[Bendude14]

just change it to this then and see i echo the string outside of the loop

 

<?php
$count = 3;
for ($i=1; $i <= $count; $i++) {
     $text .= "This is line number $i<br>\n"; 
 }

 echo $text;
?>

[kenrbnsn]

When there is only one line in an "if" block or any type of loop, you don't need the curly braces.

 

If you want to assign the value to a string and then print it:

<?php
$count = 3;
$string = '';
for ($i=1; $i <= $count; $i++)
     $string .= "This is line number $i<br>\n";
echo $string;
?>

or

<?php
$count = 3;
$tmp = array();
for ($i=1; $i <= $count; $i++)
     tmp[] =  "This is line number $i";
$string = implode("<br>\n",$tmp) . "<br>\n";
echo $string;
?>

 

Ken

[kalevra]

Thank you works fine!

[Lodius2000]

thanks for the clarifier ken,

I didnt know that