[SOLVED] Search MySql help please?

TheStalker · July 17, 2008

Hi ive been following a book to try and create a search page that searchs my database table and displays the results in a table. Im having trouble with making it work i think there maybe a problem with the form im trying to use? all i get is a page in IE showing this with the url http://localhost/test4/%3C?=$PHP_SELF?> would some one be able to point to what might be wrongin my code please?

The website declined to show this webpage

HTTP 403

Most likely causes:

This website requires you to log in.

What you can try:

Go back to the previous page.

More information

here is the code im using

<html>


<h2>Search</h2> 
<form name="search" method="post" action="<?=$PHP_SELF?>">
Seach for: <input type="text" name="find" /> 
<Select NAME="field">
<Option VALUE="fname">surname</option>
<Option VALUE="lname">forname</option>
<Option VALUE="info">postcode</option>
</Select>

<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>

<? php
//if they have submitted the form 
if ($searching =="yes") 
{ 
echo "<h2>Results</h2><p>"; 

//did not enter a search term we give  an error 
if ($find == "") 
{ 
echo "<p>You forgot to enter a search term"; 
exit; 
} 

// connect to our Database 
mysql_connect("localhost", "root", "") or die(mysql_error()); 
mysql_select_db("randv") or die(mysql_error()); 

// preform filtering 
$find = strtoupper($find); 
$find = strip_tags($find); 
$find = trim ($find); 

//Now we search the table and filed 
$data = mysql_query("SELECT * FROM customers WHERE upper($field) LIKE'%$find%'"); 


//display the results 
echo "<table width=90% align=center border=1><tr>";
while($result = mysql_fetch_array( $data )) 
{ 
$surname = $row["surname"]; 
$forename = $row["forename"]; 
$addressLine1 = $row["addressLine1"]; 
$addressLine2 = $row["addressLine2"]; 
$postcode = $row["postcode"]; 
echo "<tr> 
<td>$surname</td> 
<td>$forname</td> 
<td>$addressLine1</td> 
<td>$addressLine2</td>
<td>$postcode</td></tr> 
<tr></td> 
</tr></table>"; 
} 

//This counts the number or results 
$anymatches=mysql_num_rows($data); 
if ($anymatches == 0) 
{ 
echo "Sorry, but we can not find an entry to match the search<br><br>"; 
} 

//what was searched for
echo "<b>Searched For:</b> " .$find; 
} 
?> 

</html>

any ideas would be great thanks.

Xurion · July 17, 2008

You're assuming the searching field in for form automatically gives you the $searching variable in the script, which is not the case. You'll need to reference the posted data using:

if ($_POST['searching'] == "yes"){

HelpMe1985 · July 17, 2008

<html>


<h2>Search</h2> 
<form name="search" method="post" action="<?php=$PHP_SELF?>">
Seach for: <input type="text" name="find" /> 
<Select NAME="field">
<Option VALUE="fname">surname</option>
<Option VALUE="lname">forname</option>
<Option VALUE="info">postcode</option>
</Select>

<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>


<?php 
//if they have submitted the form 
if ($_POST['searching'] == "yes")
{ 
echo "<h2>Results</h2><p>"; 

//did not enter a search term we give  an error 
if ($find == "") 
{ 
echo "<p>You forgot to enter a search term"; 
exit; 
} 

// connect to our Database 
mysql_connect("localhost", "root", "") or die(mysql_error()); 
mysql_select_db("randv") or die(mysql_error()); 

// preform filtering 
$find = strtoupper($find); 
$find = strip_tags($find); 
$find = trim ($find); 

//Now we search the table and filed 
$data = mysql_query("SELECT * FROM customers WHERE upper($field) LIKE'%$find%'"); 


//display the results 
echo "<table width=90% align=center border=1><tr>";
while($result = mysql_fetch_array( $data )) 
{ 
$surname = $row["surname"]; 
$forename = $row["forename"]; 
$addressLine1 = $row["addressLine1"]; 
$addressLine2 = $row["addressLine2"]; 
$postcode = $row["postcode"]; 
echo "<tr> 
<td>$surname</td> 
<td>$forname</td> 
<td>$addressLine1</td> 
<td>$addressLine2</td>
<td>$postcode</td></tr> 
<tr></td> 
</tr></table>"; 
} 

//This counts the number or results 
$anymatches=mysql_num_rows($data); 
if ($anymatches == 0) 
{ 
echo "Sorry, but we can not find an entry to match the search<br><br>"; 
} 

//what was searched for
echo "<b>Searched For:</b> " .$find; 
} 
?> 

</html>

TheStalker · July 17, 2008

hi,

thanks for the quick reply. Ive changed that but im still having the same problem

search2.php

<html>


<h2>Search</h2> 
<form name="search" method="post" action="<?php=$PHP_SELF?>">
Seach for: <input type="text" name="find" /> 
<Select NAME="field">
<Option VALUE="fname">surname</option>
<Option VALUE="lname">forname</option>
<Option VALUE="info">postcode</option>
</Select>

<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>


<?php 
//if they have submitted the form 
if ($_POST['searching'] == "yes")
{ 
echo "<h2>Results</h2><p>"; 

//did not enter a search term we give  an error 
if ($find == "") 
{ 
echo "<p>You forgot to enter a search term"; 
exit; 
} 

// connect to our Database 
mysql_connect("localhost", "root", "") or die(mysql_error()); 
mysql_select_db("randv") or die(mysql_error()); 

// preform filtering 
$find = strtoupper($find); 
$find = strip_tags($find); 
$find = trim ($find); 

//Now we search the table and filed 
$data = mysql_query("SELECT * FROM customers WHERE upper($field) LIKE'%$find%'"); 


//display the results 
echo "<table width=90% align=center border=1><tr>";
while($result = mysql_fetch_array( $data )) 
{ 
$surname = $row["surname"]; 
$forename = $row["forename"]; 
$addressLine1 = $row["addressLine1"]; 
$addressLine2 = $row["addressLine2"]; 
$postcode = $row["postcode"]; 
echo "<tr> 
<td>$surname</td> 
<td>$forname</td> 
<td>$addressLine1</td> 
<td>$addressLine2</td>
<td>$postcode</td></tr> 
<tr></td> 
</tr></table>"; 
} 

//This counts the number or results 
$anymatches=mysql_num_rows($data); 
if ($anymatches == 0) 
{ 
echo "Sorry, but we can not find an entry to match the search<br><br>"; 
} 

//what was searched for
echo "<b>Searched For:</b> " .$find; 
} 
?> 

</html>

TheStalker · July 17, 2008

ive just tried changing this

search2.php
<form name="search" method="post" action="<?php=$PHP_SELF?>">

to this

<form name="search" method="post" action="<?php echo $_SERVER['PHP_SELF']?>">

but i get this "Results

You forgot to enter a search term"

DeanWhitehouse · July 17, 2008

dont echo it,

TheStalker · July 17, 2008

<form name="search" method="post" action="<?php $_['PHP_SELF']?>">

still get :

Results

You forgot to enter a search term

its like it not seeing that any thing has been entered in the text box

DeanWhitehouse · July 17, 2008

it should be this

action="<?php $_SERVER['PHP_SELF']?>">

TheStalker · July 17, 2008

it should be this

action="<?php $_SERVER['PHP_SELF']?>">

ive changed it to this, Still get the same thing happen.

unkwntech · July 17, 2008

my suggestion would be just to change action=<? $_SERVER['PHP_SELF'] ?>

to

action='fileName.php'

TheStalker · July 17, 2008

my suggestion would be just to change action=<? $_SERVER['PHP_SELF'] ?>

to

action='fileName.php'

dosnt seem to make any diffrence?

im thinking it must be some thing within this bit of code but cant work out what

<html>


<h2>Search</h2> 
<form name="search" method="post" action="<?php $_SERVER['PHP_SELF']?>">

Seach for: <input type="text" name="find" /> 
<Select NAME="field">
<Option VALUE="surname">surname</option>
<Option VALUE="forename">forename</option>
<Option VALUE="postcode">postcode</option>
</Select>

<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>


<?php 
//if they have submitted the form 
if ($_POST['searching'] == "yes")
{ 
echo "<h2>Results</h2><p>"; 

//did not enter a search term we give  an error 
if ($find == "") 
{ 
echo "<p>You forgot to enter a search term"; 
exit; 
} 

// connect to our Database 
mysql_connect("localhost", "root", "") or die(mysql_error()); 
mysql_select_db("randv") or die(mysql_error()); 

// preform filtering 
$find = strtoupper($find); 
$find = strip_tags($find); 
$find = trim ($find); 

//Now we search the table and filed 
$data = mysql_query("SELECT * FROM customers WHERE upper($field) LIKE'%$find%'");

unkwntech · July 17, 2008

<?php
//did not enter a search term we give  an error 
if ($find == "") 
{ 
echo "<p>You forgot to enter a search term"; 
exit; 
} 
?>

should be

<?php
//did not enter a search term we give  an error 
if ($_POST['find'] == "") 
{ 
echo "<p>You forgot to enter a search term"; 
exit; 
} 
?>

Anytime you pass info from a form you need to access it either via $_POST or $_GET depending on the method you use on the form.

TheStalker · July 17, 2008

that seems to get me past that. Thanks very much just got some problems with displaying the data in the table now, but ill have a play around with that for a bit.

TheStalker · July 17, 2008

ok well ive changed a fair few things but am still can not get the results to display in the table? i get this message Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\wamp1\www\test4\search2.php on line 54

<html>
<h2>Search</h2> 
<form name="search" method="post" action="<?php $_SERVER['PHP_SELF']?>">

Seach for: <input type="text" name="find" /> 
<Select NAME="field">
<Option VALUE="Surname">Surname</option>
<Option VALUE="Forename">Forename</option>
<Option VALUE="Postcode">Postcode</option>
</Select>

<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>

<?php 
//if they have submitted the form 
if ($_POST['searching'] == "yes")
{ 
echo "<h2>Results</h2><p>"; 

//did not enter a search term we give  an error 
if ($_POST['find'] == "") 
{ 
echo "<p>You forgot to enter a search term"; 
exit; 
} 

// connect to our Database 
mysql_connect("localhost", "root", "") or die(mysql_error()); 
mysql_select_db("randv") or die(mysql_error()); 

// preform filtering 
$find = strtoupper($find); 
$find = strip_tags($find); 
$find = trim ($find);

// search the table and filed 
$data = mysql_query("SELECT * FROM customers WHERE upper($field) LIKE'%$find%'"); 

echo "<table border='1' width = '1200' align='center'>
<br>
<tr>
<th>CustomerID</th>
<th>Surname</th>
<th>Forename</th>
<th>AddressLine1</th>
<th>AddressLine2</th>
<th>Postcode</th>
</tr>";

//And we display the results 
while($row = mysql_fetch_array($data)) 

{ 
 echo "<tr>";
 echo "<td><center>" . $row['CustomerID'] . "</td>";
 echo "<td><center>" . $row['Surname'] . "</td>";
 echo "<td><center>" . $row['Forename'] . "</td>";
 echo "<td><center>" . $row['AddressLine1'] . "</td>";
 echo "<td><center>" . $row['AddressLine2'] . "</td>";
 echo "<td><center>" . $row['Postcode'] . "</td>";
 echo "</tr>";
} 



//what was searched for
echo "<b>Searched For:</b> " .$find; 
} 
?> 

</html>

TheStalker · July 17, 2008

think ive just worked this out needed to add

$find = $_POST['find'];

$field = $_POST['field'];

Sign In

[SOLVED] Search MySql help please?

Recommended Posts

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Archived

Important Information