Domestics Posted July 18, 2008 Share Posted July 18, 2008 Hello everyone, I have come accross a strange problem. For over a year now this script has worked perfectly, without fail and no problems. Today, the following message is shown when performing an action which has been run daily for the past year: MySQL Error Occured 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 QUERY = SELECT * FROM CubeCart_category WHERE cat_id= Now this is only done when running the "kelkoo" action. However, to show you the code we use on our cubecart store when performing this action it is the following: include("../../includes/ini.inc.php"); include("../../includes/global.inc.php"); require_once("../../classes/db.inc.php"); $db = new db(); include_once("../../includes/functions.inc.php"); $config = fetchDbConfig("config"); include_once("../../language/".$config['defaultLang']."/lang.inc.php"); $enableSSl = 1; include_once("../../includes/sslSwitch.inc.php"); include("../../includes/currencyVars.inc.php"); include("../includes/auth.inc.php"); if(isset($_GET['action']) && $_GET['action']=="kelkoo"){ $db = new db(); $query = "SELECT * FROM ".$glob['dbprefix']."CubeCart_kelkoo ORDER BY id desc"; $results = $db->select($query); if($results==TRUE) { for($i=0; $i<count($results); $i++){ $query = "SELECT * FROM ".$glob['dbprefix']."CubeCart_inventory WHERE productId=".$results[$i]['productId']; $name = $db->select($query); $query = "SELECT * FROM ".$glob['dbprefix']."CubeCart_cats_idx WHERE productId=".$results[$i]['productId']; $catId = $db->select($query); $query = "SELECT * FROM ".$glob['dbprefix']."CubeCart_category WHERE cat_id=".$catId[0]['cat_id']; $catname = $db->select($query); $salePrice = salePrice($name[0]['price'], $name[0]['sale_price']); if($salePrice > 0){ $price = $salePrice; } else { $price = $name[0]['price']; } $desc = str_replace(array(" ","\t","\r","\n","\0","\x0B"," "),"",strip_tags($name[0]['description'])); $desc = str_replace(" ","",$desc); if($name[0]['image']){ $image =$glob['storeURL']."/images/uploads/".$name[0]['image']; } else { $image =$glob['storeURL']."/skins/".$config['skinDir']."/styleImages/nophoto.gif"; } $kelkooContent .= "Household Appliances|".$results[$i]['type']."|".$catname[0]['cat_name']."|".$name[0]['productCode']."|||||||".$name[0]['productCode']."|".$desc."||".$image."|".$glob['storeURL']."/index.php?act=viewProd&productId=".$name[0]['productId']."|".$price."|".$results[$i]['delivery']."||In Stock||New|Single Product|0.01\r\n"; } $filename = "KelkooFeed_"; $contentLength = strlen($kelkooContent); $content = $kelkooContent; $filename .= date("dMy").".txt"; header('Pragma: private'); header('Cache-control: private, must-revalidate'); header("Content-Disposition: attachment; filename=".$filename); header("Content-type: text/plain"); header("Content-type: application/octet-stream"); header("Content-length: ".$contentLength); header("Content-Transfer-Encoding: binary"); echo $content; exit; } } I have checked and no server updates have been performed, infact nothing has changed but its suddenly not working. To explain its function, there is a working script which adds products to a table along with selected attributes such as a product type and a delivery cost. The script then generates a feed to use on the kelkoo price comparion website with those products selected (those added in the kelkoo table) collecting information required from those tables relevant. MYSQL Version: 5.0.22 Any ideas? I have already tried: -Restarting the webserver / mysqlserver -Rolling back the data to yestoday where the script worked perfectly but it seems it dosnt work still. Thank you for your help in advance. Domestics Quote Link to comment Share on other sites More sharing options...
fenway Posted July 23, 2008 Share Posted July 23, 2008 Can we see the actual query that caused that error? Quote Link to comment Share on other sites More sharing options...
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