Sideclef Posted August 13, 2008 Share Posted August 13, 2008 I am having a lot of problems with this code When I try to use the [/img] it is showing the in test and the url of the image instead of just showing the image this is what shows http://i164.photobucket.com/albums/u13/smzbjb/something.png I cant figure it out heres the code $quote2 = str_replace(" [center]","<center>", $quote2); $quote2 = str_replace("[/center] ","</center>", $quote2); $begin = ""; $end = strtolower($quote2); while( !empty( $end ) ) { $p = strpos( strtolower( $end ), "[img]"); if( $p === FALSE ) { $begin = $begin . $end; $end = ""; } else { $begin = $begin . substr( $end, 0, $p ); $end = substr( $end, $p ); $p = strpos( $end, "[/img]" ); if( $p === FALSE ) { $p = strlen( $end ); } $p = ($p - 5); $url = substr( $end,5, $p ); list($width, $height, $type, $attr) = @getimagesize( $url ); if ($width > 450) { $begin = $begin . "<center><img width=450 src=\"$url\"><br/></center>"; } else { $begin = $begin . "<center><img % src=\"$url\"></center>"; } $end = substr( $end, strlen( $url ) ); $end = substr( $end,5); } } // $quote2 = $begin; $quote2 = str_replace("[/img]","", $quote2); $quote2 = str_replace("[/img]","", $quote2); Quote Link to comment Share on other sites More sharing options...
Sideclef Posted August 13, 2008 Author Share Posted August 13, 2008 sorry I messed up the post here it is corrected I am having problems getting the code to work it shows [img] http://i164.photobucket.com/albums/u13/smzbjb/something.png as the result instaed of showing the image I have no idea whats wrong been working on it for days. $quote2 = str_replace(" [center]","<center>", $quote2); $quote2 = str_replace("[/center] ","</center>", $quote2); $begin = ""; $end = strtolower($quote2); while( !empty( $end ) ) { $p = strpos( strtolower( $end ), "[img]"); if( $p === FALSE ) { $begin = $begin . $end; $end = ""; } else { $begin = $begin . substr( $end, 0, $p ); $end = substr( $end, $p ); $p = strpos( $end, "[/img]" ); if( $p === FALSE ) { $p = strlen( $end ); } $p = ($p - 5); $url = substr( $end,5, $p ); list($width, $height, $type, $attr) = @getimagesize( $url ); if ($width > 450) { $begin = $begin . "<center><img width=450 src=\"$url\"><br/></center>"; } else { $begin = $begin . "<center><img % src=\"$url\"></center>"; } $end = substr( $end, strlen( $url ) ); $end = substr( $end,5); } } // $quote2 = $begin; $quote2 = str_replace("[/img]","", $quote2); $quote2 = str_replace("[/img]","", $quote2); Quote Link to comment Share on other sites More sharing options...
DarkWater Posted August 13, 2008 Share Posted August 13, 2008 Why not just use a regex...? <?php $text = "[img=http://i164.photobucket.com/albums/u13/smzbjb/something.png]"; preg_replace('/[img](.+?)[\/img]/i', '<img src="$1" />', $text); ?> Quote Link to comment Share on other sites More sharing options...
Sideclef Posted August 13, 2008 Author Share Posted August 13, 2008 I fixed it thanks for the help Quote Link to comment Share on other sites More sharing options...
thebadbad Posted August 13, 2008 Share Posted August 13, 2008 Why not just use a regex...? <?php $text = "[img=http://i164.photobucket.com/albums/u13/smzbjb/something.png]"; preg_replace('/[img](.+?)[\/img]/i', '<img src="$1" />', $text); ?> You forgot to escape the square brackets. Just in case the OP is using your code.. Quote Link to comment Share on other sites More sharing options...
DarkWater Posted August 13, 2008 Share Posted August 13, 2008 Yeah, I know. >_< I realized it after my editing time was over, lol. I tried it and realized "oh hey it didn't work, let me escape those". Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.