dkphp2 Posted June 14, 2006 Share Posted June 14, 2006 [code]<?php $brokerage = "{listing_field_ListingOfficeID_value}"; if ($brokerage != "999"){ echo "<p>foo</p>"; echo "brokerage=$brokerage"; } else { echo "<p>my broker</p>"; echo "brokerage=$brokerage"; } ?> [/code]I am trying to get it to work within an Open Realty template and {listing_field_ListingOfficeID_value} is one of the fields you can place on the page within the templating system. It appears to be parsing the PHP, but I can't ever get it to behave like I need it to. I've tried single & double quotes around the $brokerage assignment and comparison in the if statement. I've tried using == to compare instead of !=. Switching the comparison does switch which code is executed, but the statement never evaluates like I need it to. When it echoes the $brokerage variable to the page, it is always correct...but the comparison does not appear to be correct. What I am trying to get it to do is check the ListingOfficeID, and if it is not mine then it will display a logo denoting that it is listed by another broker.Any suggestions for what I am doing wrong? Quote Link to comment https://forums.phpfreaks.com/topic/12032-problem-with-an-if-statement/ Share on other sites More sharing options...
phpvolution Posted June 15, 2006 Share Posted June 15, 2006 Edit: actually now that I think about it. At the time of the if-statement comparison, your $brokerage variable is still translated as {listing_field_ListingOfficeID_value}, not a number.but when you echo it it is then parsed into your ID such as 999. So that is a pretty complex problem, and I'm not sure how you can code a work around for it. I may have to tinker some more to figure that out :p Quote Link to comment https://forums.phpfreaks.com/topic/12032-problem-with-an-if-statement/#findComment-45803 Share on other sites More sharing options...
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