preg_replace

[roydukkey]

if i have:

 

var = "/Assignment1/images/doors"

 

how can i use preg_replace to gain:

 

var = "/Assignment1/images"

 

Thanks

roydukkey

[nrg_alpha]

You can use something like:

 

$str = '/Assignment1/images/doors';
$str = preg_replace('#(/\w+)$#', '', $str);
echo $str;

 

EDIT:

If you need to have the 'var =' in there, simply replace the first line in the snippet above with:

$str = 'var = /Assignment1/images/doors';

 

However, I have a feeling var is supposed to be a string variable (which misses the $ before it).. so just replace any '$str' part in the code with $var...

[effigy]

The parentheses are unnecessary: #/\w+$#.

[nrg_alpha]

You're right. I have a bad habit of gouping (I suppose I have to be more mindful of un-necessary grouping as it creates extra work for regex).

[roydukkey]

ok but there is a problem, this works great until there are hyphens in the variable. ex.

 

$str = '/Assignment1/images/doors/09-10-2008';
$str = preg_replace('#(/\w+)$#', '', $str);
echo $str;

 

$str equals '/Assignment1/images/doors/09-10-2008' when

$str should equal '/Assignment1/images/doors'

 

How could this be fixed? thx

[nrg_alpha]

Is this what you are looking for?

 

//$str = '/Assignment1/images/doors/09-10-2008'; //  ouputs   /Assignment1/images/doors
//$str = '/Assignment1/images/doors'; //  outputs  /Assignment1/images
$str = preg_replace('#/[^/]+$#', '', $str);
echo $str;

 

Alternate Uncommenting one, then the other. This should be along the lines of what you are looking for.

 

 

[Zane]

If that's all you're trying to do is get the end part of all the slashes, you should just be able to use pathinfo()

$str = '/Assignment1/images/doors/09-10-2008';
$strInfo = pathinfo($str);
echo $strInfo['basename'] //