[SOLVED] Displaying an image using PHP

[yddib]

Hi lads,

My code here may well be kinda ridiculous, all my PHPing is basically flailing in the dark until something works.

 

Basically i have a URL to an image stored in my database, and I want to be able to pull out different URLs with PHP and display the actual images. at the moment i'm just getting a red X. I can get the URL out no bother, it's making it into an actual image that's the problem.

 

At the moment i'm doing

 

$result = @mysql_query("SELECT pic FROM gradinfo where email ='$email' and pass ='$pass' ");
if (!$result) {
exit('Error performing query: ' . mysql_error());
}

while ($row = mysql_fetch_array($result)) {
echo "<img src=<'".$row['pic']."'>";

}  

 

 

Any suggestions appreciated, thanks!

[JasonLewis]

echo "<img src='".$row['pic']."' />";

 

Should display the pic. If it isn't, check what the address is by Right Clicking the red X and going to Properties. It should have the address of the image.

[yddib]

Works a treat. Thanks very much. Can't believe it was that simple.. been trying to get that working for hours and hours!