[SOLVED] form checkbox help

sasori · September 9, 2008

I have data in the table products as follows

,cid,cat,,,
,'1','Furniture',,,
,'2','Toys',,,
,'3','Clothes',,,
,'4','Food',,,

then i created this simple script

include('db.php');
$cxn = mysqli_connect($host,$user,$pwd,$db) or die ("can't connect");
$query = "SELECT DISTINCT cat FROM products ORDER BY cat";
$result = mysqli_query($cxn,$query) or die ("can't connect");
echo "<form action='process.php' method='post'>";
while($row = mysqli_fetch_assoc($result))
{
  extract($row);
  echo "<input type='checkbox' name='category[$cat]' value='$cat' />\n";
  echo "<label for='$cat'>$cat</label>";
}
echo "<input type='submit' value='select category' />";
echo "</form>";

the question now is, why is that after i selected a category from the check box,

then onclicked the submit button. the output says

"Category = Array"

I don't know what am missing in my code, help me configure this thing out Sir/s ???

pocobueno1388 · September 9, 2008

Because you set it up to be an array in your form.

After the submit button is pressed, do this to see what the array contains

echo '<pre>',print_r($_POST['category']),'</pre>';

sasori · September 9, 2008

Because you set it up to be an array in your form.

After the submit button is pressed, do this to see what the array contains
echo '<pre>',print_r($_POST['category']),'</pre>';

I already have a 'process.php' that outputs an the $_POST array sir

<?php
echo "<html><head><title>Hello Telephone</title></head>\n";
echo "<body>\n";
echo "<ol>\n";
foreach($_POST as $field => $value)
{
    echo "<li>$field = $value</li>\n";
}
echo "</ol>\n";
echo "<form action='dryrun.php' method='GET'>\n";
echo "<input type='submit' value='back' />\n";
echo "</form>\n";
echo "</body>\n";
echo "</html>\n";
?>

i got confused more with your tip i don't understand what to do now lol

pocobueno1388 · September 9, 2008

Try chaning

foreach($_POST as $field => $value)

To

foreach($_POST['category'] as $field => $value)

sasori · September 9, 2008

Try chaning

foreach($_POST as $field => $value)

To

foreach($_POST['category'] as $field => $value)

i did just did your tip .. and it ruined the supposed to be output, istead of

1. Category = Furniture ...the output is now Furniture = Furniture

and also the other blocks that uses my 'process.php' code where ruined

here's my actual practice code

<?php
include('db.php');
echo "<html>\n";
echo "<head><title>Practice Shit</title></head>\n";
echo "<body>\n";
// CUSTOMER DETAIL
echo "<fieldset><b><legend>Customer</legend></b>\n";
$labels = array("fname" => "first name",
                "lname" => "last name",
                "phone" => "phone number");

$submit = "details";
echo "<div align='center'>\n";
echo "<form action='process.php' method='POST'>\n";
foreach($labels as $field => $label)
{
    echo "<label for='$field'>$label</label> \n";
    echo "<input type='text' name='$field' size='15%' maxlength='15'/>\n";
}
echo "<input type='submit' value='$submit'>\n";
echo "</form>\n";
echo "</div>\n";
echo "</fieldset>\n";
// CATEGORIES MENU
$cxn = mysqli_connect($host,$user,$pwd,$db) or die ("can't connect");
$query = "SELECT cat FROM products ORDER BY cat ASC";
$result = mysqli_query($cxn,$query) or die ("can't connect");
echo "<fieldset><b><legend>Categories</legend></b>\n";
echo "<div align='center'>\n";
echo "<form action='process.php' method='POST'>\n";
echo "<select name='Category'>\n";
while($row = mysqli_fetch_assoc($result))
{
  extract($row);
  echo "<option value='$cat'>$cat</option>\n";
}
echo "</select>\n";
echo "<input type='submit' value='select' category'>\n";
echo "</form>\n";
echo "</div>\n";
echo "</fieldset>\n";

//DATE
$months = array("January","February","March","April","May",
                "June","July","August","September","October","November",
                "December");

echo "<fieldset><b><legend>Date</legend></b>\n";
echo "<div align='center'>\n";
echo "<form>\n";
echo "<select name='Month'>\n";
foreach($months as $value)
{
  echo "<option value='$value'";
  if($value == date('F',time()))
  {
    echo " selected ";
  }
  echo "> $value</option>\n";
}
echo "</select>\n";
echo "<select name='Day'>\n";
for($i=1;$i<=31;$i++)
{
    echo "<option value='$i' ";
    if($i == date('d',time()))
    {
      echo " selected ";
    }
    echo "> $i</option>\n";
}
echo "</select>\n";
echo "<select name='Year'>\n";
$year = date('Y');
for($i=$year;$i<=$year+3;$i++)
{
  echo "<option value='$i'";
  if($i == $year)
  {
    echo " selected ";
  }
  echo "> $i </option>\n";
}
echo "</select>\n";
echo "</form>\n";
echo "</div>\n";
echo "</fieldset>\n";
//RADIO BUTTONS

echo "<fieldset><b><legend>Categories</legend></b>\n";
echo "<div align='center'>\n";
echo "<form action='process.php' method='POST'>\n";
$query2 = "SELECT cat FROM products ORDER BY cat";
$result3 = mysqli_query($cxn,$query2) or die ("can't connect");
while($row = mysqli_fetch_assoc($result3))
{
  extract($row);
  echo "<input type='radio' name='Category' value='$cat' />$cat\n";
  echo "<br/>\n";
}
echo "<input type='submit' value='select category' />";
echo "</form>";
echo "</div>\n";
echo "</fieldset>";
echo "<fieldset><b><legend>CheckBox</legend></b>\n";
$query = "SELECT DISTINCT cat FROM products ORDER BY cat";
echo "<form action='process.php' method='post'>\n";
$result4 = mysqli_query($cxn,$query) or die ("can't connect");
while($row = mysqli_fetch_assoc($result4))
{
  extract($row);
  echo "<input type='checkbox' name='category[$cat]' id='$cat' value='$cat' />\n";
  echo "<label for ='$cat'>$cat</label>\n";
}
echo "<input type='submit' value='select category'>\n";
echo "</fieldset>\n";
echo "</body>\n";
echo "</html>\n";
mysqli_close($cxn);
?>

what should i do now? all other blocks are using that process.php so when i changed the $_POST attribute ..the code gone crazy

pocobueno1388 · September 9, 2008

Okay, lets try this.

Erase this

echo "<ol>\n";
foreach($_POST as $field => $value)
{
    echo "<li>$field = $value</li>\n";
}
echo "</ol>\n";

and put in

echo '<pre>',print_r($_POST),'</pre>';

Copy and paste what that gives you.

sasori · September 9, 2008

Okay, lets try this.

Erase this
echo "<ol>\n";
foreach($_POST as $field => $value)
{
    echo "<li>$field = $value</li>\n";
}
echo "</ol>\n";
and put in
echo '<pre>',print_r($_POST),'</pre>';
Copy and paste what that gives you.

and now this is the ouput after doing that

pocobueno1388 · September 9, 2008

So what's the problem with the output, how do you WANT it to be? The output makes sense to me if your only checking one checkbox. Is that what your doing?

sasori · September 9, 2008

So what's the problem with the output, how do you WANT it to be? The output makes sense to me if your only checking one checkbox. Is that what your doing?

the out put is supposed to be, let's say I clicked the checkbox with name Furniture,

it should be

1.) Category = Furniture

that's why the rest of the code are being messed up if I change the $_POST in process.php

sasori · September 9, 2008

I was able to configure the problem myself, first, i created a process2.php for the checkbox to use

in processing the submit button

$category = array("Clothes","Food","Furnitures","Health","Toys");
echo "<ol>\n";
foreach($_POST as $category)
{
foreach($category as $field => $value)
{
	echo "<li>Category = $value</li>\n";
}
}

cheers

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[SOLVED] form checkbox help

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