Basic help (i think)

[brucehere]

Hi,

I have some simple code that pulls some images from a gallery on my site and displays them on the frontpage. (Its in Drupal)

<?php

$numImage = 4;

$images = image_get_random($numImage);

 

for($i=0;$i<count($images);$i++) {

    echo l(image_display($images[$i], 'thumbnail'), 'node/'. $images[$i]->nid, array('html' => TRUE));

}

?>

 

That works and everything great.

But it displays the thumbnails all right next to each other. Id like there to be a small space between them and if possible on the same horizontal path. At the mo some are portrait orientation and some landscape, which makes it look a bit funny.

It isn't the biggest issue if that cant be done.

Otherwise just the spacing would be great. (sorry im not the strongest in php!)

[lisa71283]

Add a "padding-right: x;" attribute to the image, either using its CSS class, or an inline style="xyz" attribute to the IMG tag.

[brucehere]

I couldn't find the CSS file for it. I dont think there is one as this is a custom block Ive created.

 

Is there any way I could just add some code into the PHP to create the breaks/alignment?

[lisa71283]

<img src="whatever.png" style="padding-right: 15px;" alt="description" />

[brucehere]

I cannot specify items to the image tag.

As its constantly changing with various random images from a single gallery.

All php based.

If that is the code i should add into the PHP, please show me exactly where to put it?

Sorry, my knowledge is very simple around this area.

[BlueSkyIS]

after you echo the image,

echo ' ';

[brucehere]

sorry.

im really bad at this. jsut getting errors...

where exactly do i place that bit of code?

[BlueSkyIS]

on a line after the only line containing echo. we're trying to add a   (HTML non-breaking space) after each image is echoed.

[brucehere]

ya, i can see that. However i have tried 100's of options now and still dont know the exact place to put it in??

PLease can you copy and paste my code with the correct &nbsp spacing code in it.

Thanks.

[lisa71283]

We cannot modify your code, as the snippet posted does not produce the output. The snippet posted calls image_display(), which either generates the HTML itself, or passes the arguments to another function. You will need to look at the source for image_display() and let us know if it is creating the HTML <IMG> tag. Once we find the code that is actually producing the HTML, then we can modify it as necessary.