0 or 1 quote

[The Little Guy]

I have this:

$findL = array(
	'~<a(.+?)href=\"{0,1}(http|https)://(.+?)\"{0,1}~',
	'~<a(.+?)href=\"{0,1}/(.+?)\"{0,1}~');
$replaceL = array(
	'<a$1href="http://dudeel.com/lProxy?p=$2://$3"',
	'<a$1href="http://dudeel.com/lProxy?p='.$domain.'/$2"');
$f = preg_replace($findL,$replaceL,$f,-1);

 

You see where the " are?

 

How do I say 0 or 1 quote?

[genericnumber1]

the problem with the way you're doing it now is that you're not definite with whether it will indeed end with a quote or not... if it doesn't, in fact, end with a quote it has no idea where the (.+?) ends in your pattern... you need to add more to define where the end is.. something that always exists, in this case I would guess a >. But I digress, to check to see if something exists 1 or 0 times, you just need to use ?... so something like

<a(.*?)href(\s*?)=(\s*?)"?(http|https)://(.*?)"?(.*?)>

would suffice. I tried to make it match pretty much any coding style of a tag, you can of course change it how you want it.

[The Little Guy]

It doesn't work with the ? after the "

 

Note: I have exactly what I had before, I just changed: {0,1} to ?

[genericnumber1]

it's working for me :X but it's a bit late for me to stay on, I'll be back to this topic tomorrow. You don't need to escape the double quotes btw.

[The Little Guy]

bump

[effigy]

An example of optional quotes can be found here.