[SOLVED] upload a file twice??

[Alkimuz]

Hey, i want to save an uploaded picture to two different locations, is that possible? if so, how?

 

now, i let a user upload a picture and my code resizes the picture and stores it at a specific location, but i like to resize it for a second time and store that picture at a second location, but it seems that if i run the uploadcode twice, the original temporary sourcedata ( where $_FILES[$filename]['tmp_name'] points to) is deleted?

 

the code i use at the moment is the following, any suggestions how i can expand it, or repeat it so that it resizes the original picture twice and stores it twice?

 

function photoupload($filename, $source, $path, $name, $MaxX, $MaxY)
{
/*START PHOTOUPLOAD*/
if (trim($_FILES[$filename]['tmp_name']) == TRUE)
   {

   $destination = $path.$name.'-'.$_FILES[$filename]['name'] ;

      
// Does the file have the right MIME type?

   if ($_FILES[$filename]['type'] != 'image/pjpeg' AND $_FILES[$filename]['type'] != 'image/jpeg' AND $_FILES[$filename]['type'] != 'image/gif' AND $_FILES[$filename]['type'] != 'image/png' AND $_FILES[$filename]['type'] != 'image/wbmp')
      {
      echo 'the file you want to upload is no photo, please go back to try again';
      exit;
      }



	// Get current dimensions

    list($width_orig, $height_orig) = getimagesize($source);


       // Check if they are over their limit

       if ( ($width_orig > $MaxX) || ( $height_orig > $MaxY))

          {

          if ($MaxX && ($width_orig < $height_orig)) 
				  {
					$MaxX = ($MaxY / $height_orig) * $width_orig;
					} 
				else 
					{
					$MaxY = ($MaxX / $width_orig) * $height_orig;
					}

		   // Resample voorbereiden
		   $image_p = imagecreatetruecolor($MaxX, $MaxY);
			 $image_type = strtolower( substr($destination, strrpos( $destination, '.' )) );

			 switch( $image_type )
			   {
				 case '.gif' :  $image = imagecreatefromgif($source);  break;
				 case '.jpg' :  $image = imagecreatefromjpeg($source); break;
				 case '.jpeg':  $image = imagecreatefromjpeg($source); break;
				 case '.png' :  $image = imagecreatefrompng($source);  break;
				 case '.bmp' :  $image = imagecreatefromwbmp($source); break;
				 }
		   // Resample de afbeelding

			 imagecopyresampled($image_p, $image, 0, 0, 0, 0, $MaxX, $MaxY, $width_orig, $height_orig);

				 // Output
			 switch( $image_type)
			   {
				 case '.gif'  :  imagegif($image_p, $source, 100);  break;
				 case '.jpg'  :  imagejpeg($image_p, $source, 100); break;
				 case '.jpeg' :  imagejpeg($image_p, $source, 100); break;
				 case '.png'  :  imagepng($image_p, $source, 100);  break;
				 case '.bmp'  :  image2wbmp($image_p, $source, 100);break;
				 }

         move_uploaded_file ( $source, $destination );

         } 
	else
         {
			 // Image is ok, just move it to the new location
			 move_uploaded_file ( $source, $destination );
			 }                                            



return 0;	

    }

/*END PHOTOUPLOAD*/
}

 

 

[amagondes]

hi, i'm pretty sure when you call move_uploaded_file, it does actually move the file, so your second call will not be able to find it (beacuse it has been moved). Why don't you pass the file name of first saved image to the second call as I'm guessing that is what the $source paramater is in the function declaration. hope that helps

[JasonLewis]

You can use copy() to copy the file to a new location.

[Alkimuz]

thanks! both of you!

amagondes for making me help to understand why it didnt work

projectfear for the golden tip for making my code work!

 

i didnt know the function copy, so know i do, it was not a hard job to change my not working code to a working one

 

thanks again ^^