Preg_match for decimals?

[woolyg]

Hi all,

 

I'm trying to validate a number entry - say a user enters

 

100 - allow it,

100.23 - allow it

100.234 - disallow it

100text - disallow it

 

Can anyone help me with the preg_match validator?

I've tried looking it up, but I'm getting errors regarding delimiters.

 

Thanks,

WoolyG

[corbin]

/^([0-9.]+)$/

[nrg_alpha]

/^([0-9.]+)$/

 

Corbin, the problem with this pattern is that it will even satisfy 100.234

Here is my take:

 

$str = '1004325.23';
if (preg_match('#^\d+(?:\.\d{1,2})?$#', $str, $match)){
   echo $match[0] . ' is valid!';
} else {
   echo $str . ' is NOT valid!';
}

 

This pattern assumes:

a) no limit to the amount of numbers prior to a decimal point (if there even is a decimal with digits after it)

b) if there is a decimal, there is a minimum of 1 digit, and a maximum of 2 digits).. [if the OP only wants 2 digits after the decimal, change \d{1,2} to \d{2}]

 

Cheers,

 

NRG

[The Little Guy]

or...

 

function is_valid($number){
     if(is_numeric){
          list($nu,$de) = explode('.',$number);
          return (strlen($de) < 3 || !isset($de)) ? TRUE : FALSE;
     }else{
          return FALSE;
     }
}

[nrg_alpha]

or...

function is_valid($number){
if(is_numeric){
   list($nu,$de) = explode('.',$number);
   return (strlen($de) < 3 || !isset($de)) ? TRUE : FALSE;
}else{
   return FALSE;
}
}

 

this line:

if(is_numeric){

 

should be:

if(is_numeric($number)){

 

as is_numeric is a function call that requires a single argument. With your current code, an assumed constant 'is_numeric' error occurs.

[The Little Guy]

Oops, sorry, forgot that

 

Good catch!

[corbin]

Oh hehe didn't realize he only wanted 2 decimals.