sorting list of directories by count of contents

[hellonoko]

I am trying to display a list of directories an the count of their file contents sorted by volume.

 

Have been playing around with a few things but I can't quite get it to work.

 

<?php

$dir = "/home2/sharingi/public_html/subdomains";

$dh = opendir($dir);

while (false !== ($filename = readdir($dh)))
{
	if ($filename !== "." && $filename !== "..")
	{
		//$files[] = $filename;

		//$files[] = count(glob("/home2/sharingi/public_html/subdomains/" . $filename . "/filez/" . "*.mp3"));

		$files['user'][$x] = $filename;
		$files['count'][$x] = $files[] = count(glob("/home2/sharingi/public_html/subdomains/" . $filename . "/filez/" . "*.mp3"));

		$x++;

	}
}

sort ($files);

//for $i = 0; $i < sizeof($files); $i++;
//{
//	echo $files['user'][$value];
//	echo '<br>';
//	echo $files['count'][$value];
//	echo '<br>';

//	i++;
//}

foreach ( $files as $value)
{
	echo $files['user'][$value];
	echo '<br>';
	echo $files['count'][$value];
	echo '<br>';
}

//unset $value;

//print_r($files);

?>

 

Any suggestions?

[fanfavorite]

First, make sure you define $x at the top:

 

$x = 1;

 

then change your foreach ($files as $value) to:

 

for ($count = 1;$count <= $x; $count++) {

echo $files['user'][$count];

echo '<br>';

echo $files['count'][$count];

echo '<br>';

}

[hellonoko]

Returns 0

 

should return

 

three numbers

[Zane]

$dir = "/home2/sharingi/public_html/subdomains";
$out = shell_exec("du " . $dir . " -k --max-depth=2");
foreach(preg_split("#\n#", $out) as $val)
     $thedirs[] = preg_split('#\s#', $val);

function sortSize( $a, $b ){
    if ( $a[0] == $b[0] )
        return 0;
    if ( $a[0]          return -1;
    return 1;
}
usort($thedirs, "sortSize");
foreach ($thedirs as $val)
     echo $val[1] . "          (" . $val[0] . ")
\n";
?>

[hellonoko]

no idea how this works but returns:

 

()

/home2/sharingi/public_html/subdomains/raphael/cgi-bin (4)

/home2/sharingi/public_html/subdomains/raphael/tmp (4)

/home2/sharingi/public_html/subdomains/iana/cgi-bin (4)

/home2/sharingi/public_html/subdomains/test/tmp (4)

/home2/sharingi/public_html/subdomains/iana/tmp (4)

/home2/sharingi/public_html/subdomains/test/cgi-bin (4)

/home2/sharingi/public_html/subdomains/iana/filez (4264)

/home2/sharingi/public_html/subdomains/iana (4304)

/home2/sharingi/public_html/subdomains/raphael/filez (14692)

/home2/sharingi/public_html/subdomains/raphael (14732)

/home2/sharingi/public_html/subdomains/test/filez (131628)

/home2/sharingi/public_html/subdomains/test (131668)

/home2/sharingi/public_html/subdomains (150708)

 

 

was hoping for something more like.

 

test 13

raphael 2

iana 1

[Zane]

Added some comments

$dir = "/home2/sharingi/public_html/subdomains";
//This is a Linux command to get your directories
/*
--max-depth controls the amount of directories it goes deep
-k means the size is returned in kilobytes
if you want megabytes instead do -m or -b for just bytes
*/
$out = shell_exec("du " . $dir . " -m --max-depth=1");

//This split everyone one of them each into separate lines to work with..since they're returned as a whole
foreach(preg_split("#\n#", $out) as $val)
     $thedirs[] = preg_split('#\s#', $val); //The separates the size from the dirname and puts the array

//This is a function to sort the dir's size in ascending order....
function sortSize( $a, $b ){
    if ( $a[0] == $b[0] )
        return 0;
    if ( $a[0]          return -1;
    return 1;
}
usort($thedirs, "sortSize");
foreach ($thedirs as $val)
     echo $val[1] . "          (" . $val[0] . ")
\n";
?>

[hellonoko]

I think I see how this works but isn't it still going to not work for me since I need a count of files not the size.

 

If use A had 10 files all totaling 1meg and user B had 2 files each 10megs then I still need to sort user A first.

 

Here is my newest code that reads all the info into an array. I think it works correct but I am not sure how to get it to display the info.

 

<?php

$dir = "/home2/sharingi/public_html/subdomains";

$dh = opendir($dir);



while (false !== ($filename = readdir($dh)))
{
	if ($filename !== "." && $filename !== "..")
	{

		$files['name'] = $filename;

		$files['count'] = count(glob("/home2/sharingi/public_html/subdomains/" . $filename . "/filez/" . "*.mp3"));


		echo $files['name'];
		echo '<br>';
		echo $files['count'];
		echo '<br>';

	}
}