[SOLVED] Pass php variable to another server

[lindm]

I have php scripting on two web servers:

 

On server 1 I have a php script that generates html code, stored in a variable.

 

I want to pass this variable to another php script found on server 2.

 

What is the best way to do this?

 

 

[Psycho]

Hmm, you can't pass variables like that. Simply have a script on server 2 that calls a page on server 1 which outputs the variable content.

 

Server 2 script

$outputFromServer1 = file_get_contents('http://www.server1.com/outputforserver2.php');

 

Script on server 1

$outputForServer2 = "Hello World!";
echo $outputForServer2;

[lindm]

Alright. What if the script on server 1 is protected by a userid and password?

 

(Stored in $_SESSION['username'] and $_SESSION['password'])

 

 

 

[Psycho]

Then pass that info when calling the script

 

$url = 'http://www.server1.com/outputforserver2.php?u=userid&p=password';
$outputFromServer1 = file_get_contents($url);

[lindm]

Having some problems. The script1 has this part to verify if the login is ok:

 

session_start();
if(!isset($_SESSION['username'])){
echo 'No access';
exit();
}

 

As far as I can tell the file_get_contents() doesn't take into account SESSIONS. Is this correct?

[Psycho]

Correct. You will need to change the script to also accept $_GET credentials.

 

Something along these lines:

session_start();
if( !isset($_SESSION['username']) && !isset($_GET['username']) )
{
  echo 'No access';
  exit();
}

$username = (isset($_SESSION['username']))?$_SESSION['username']:$_GET['username'];

[DarkWater]

Correct. You will need to change the script to also accept $_GET credentials.

 

Something along these lines:

session_start();
if( !isset($_SESSION['username']) && !isset($_GET['username']) )
{
  echo 'No access';
  exit();
}

$username = (isset($_SESSION['username']))?$_SESSION['username']:$_GET['username'];

 

That's really not too safe. >_>

[lindm]

Alright.

 

Thanks for all help!