[SOLVED] MYSQL Query Help

[pavanpuligandla]

hii..

i'm deleting records from mysql table.,i want to show an error message like "no records to delete" if there are 0 records in that table, else "records deleted".

below is my query for deleting records,

 

<?PHP
  include "authn.php";
//Connect to mysql server
$link=mysql_connect("localhost","root","");
if(!$link) {
	die('Failed to connect to server: ' . mysql_error());
}
//Select database
$db=mysql_select_db("cge");
if(!$db) {
	die("Unable to select database");
}

$type=$_POST['type'];
$batch=$_POST['batch'];

    $query = mysql_query("DELETE FROM `1in` WHERE CONVERT(`1in`.`Type` USING utf8) = '$type' AND CONVERT(`1in`.`Batch` USING utf8) = '$batch'") or die(mysql_error());
 if(mysql_num_rows($query)>0)  
	 {  
    
        include("in1delup.php");
     }  
  
else {  
     echo 'No records to delete';  
}  


?>

 

but i'm getting warning message as :

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\wamp\www\Project\in1delete.php on line 18

No records to delete

 

can anyone help me out in using if else condition properly..

many thanks,

pavan.p

[burnside]

I WOULD DO SOME THING LIKE THIS:

 

<?php

$conn = mysql_connect("localhost", "mysql_user", "mysql_password");

if (!$conn) {
    echo "Unable to connect to DB: " . mysql_error();
    exit;
}
  
if (!mysql_select_db("mydbname")) {
    echo "Unable to select mydbname: " . mysql_error();
    exit;
}

$sql = "SELECT id as userid, fullname, userstatus 
        FROM   sometable
        WHERE  userstatus = 1";

$result = mysql_query($sql);

if (!$result) {
    echo "Could not successfully run query ($sql) from DB: " . mysql_error();
    exit;
}

if (mysql_num_rows($result) == 0) {
    // NOTHING TO DELETE
    exit;
}


while ($row = mysql_fetch_assoc($result)) {
    // DELETE
}

mysql_free_result($result);

?> 

 

Took of the php.net manual : http://uk.php.net/manual/en/function.mysql-fetch-assoc.php

 

was to lazy to type it out.

[R4nk3d]

I think that the lines:

$query = mysql_query("DELETE FROM `1in` WHERE CONVERT(`1in`.`Type` USING utf8) = '$type' AND CONVERT(`1in`.`Batch` USING utf8) = '$batch'") or die(mysql_error());
    if(mysql_num_rows($query)>0) 
       { 
   
        include("in1delup.php");
     }

The $query line shouldnt have the actual mysql_query command on it, just the "DELETE FROM....". Cause right now, ur deleting all the rows, then asking if there are any left, so of course there wont be, u just deleted them. I dont know if im right, someone else needs to confirm this.

[pavanpuligandla]

hii...

the table contains many records based on "Type" and "Batch".. so if i'm deleting based on those variables..

ex: if type="UG" and Batch="08", then the records will be deleted are the rows having "UG" and "08" only, not other records like "PG" and "09"..

 

rite. so now my table has no "ug" type and "08" batch rows.. so if i try to delete them, i should get an error message like "no records to delete"...

hope u understand my problem..

 

even after writing if else condition also, i'm getting the same error as  shown in the above post..

pls can any one tel me idea??  ???

many thnx,

pavan.p

[fenway]

Please echo that query.

[pavanpuligandla]

helo,

 

i printed the query, i'm getting the below warning;

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\wamp\www\MyDreamProject\csin1delete.php on line 38

No records to delete1

[fenway]

No you didn't... you ran the query... please echo the query string that you're passing to mysql_query().

[Barand]

mysql_num_rows() is for queries that return a result set. DELETE queries do not.

 

Use

if (mysql_affected_rows() > 0 )

[pavanpuligandla]

@ barand,.

 

if (mysql_affected_rows() > 0 )

yes got it. mysql_num_rows is for gettin resultset..u r rite..

many thnx boss.