help with a html posting variable issue

[mgwalk]

I have a field like this the 12 is an item id attached to the name field I want to pick it up on the post.

 

<input type="checkbox" name="name12" value="12" />

 

When I submit it I try

 

if(isset($_POST['name'.$myid])) // <-- this never is works always not set...
   {
   // I can not get here even if the name12 is set...
   }
else
   {
   // I always get here
   }

 

What am I doing wrong or how do you get this to work.

 

Thanks

 

 

[DeanWhitehouse]

That made no sense at-all, but were is $myid defined, etc. we need to see proper code.

[mgwalk]

I am trying to get

isset($_POST['name'.$myid]) I am getting not set here, when I know it is set. How do you write this? $myid  is an item ID it is pulled ok I verified that.

I trying to get this isset($_POST['name12']) with my variable.

 

but I now think my error is because my input checkbox (name12) is dynamically created and not posting the field with the form.

[mgwalk]

it is not seeing my dynamic input (checkbox). Is it possible to post a dynamic checkbox written after the page has loaded? I used Javascript to create these checkboxes from data brought back from XMLHttpRequest().

[play_]

I am trying to get

isset($_POST['name'.$myid]) I am getting not set here, when I know it is set. How do you write this? $myid  is an item ID it is pulled ok I verified that.

I trying to get this isset($_POST['name12']) with my variable.

 

but I now think my error is because my input checkbox (name12) is dynamically created and not posting the field with the form.

 

If you're trying to get '$_POST['name12']', why not just do $_POST['name12'] ? i mean, name12 is the name of the checkbox.

[DeanWhitehouse]

I beleive it is dynamic, but still the if statement seems pointless if it is, so it must be hard coded.

 

Still without seing his code it is impossible to guess.