can I add many var in on var? like array?

[samoi]

hello guys

 

how are you?

 

can I merge many vars in only one var?

 

an example:

 

<?php
$conn = mysql_connect("localhost", "root", "root");
$db = mysql_select_db("data_base");

$username = $_POST['username'];
$password = $_POST['password'];

$whatever = "whatever var";

$also_a_var = "whatever added vars";

?>

 

Can any one explain how can I put all of them in only one var? and explain if there are exceptions for any functions like (isset) or any other functions.

 

 

Thank you all!

[wildboy211]

like this?

$whatever = "whatever var";

$also_a_var = "whatever added vars";
whatever2 = array($whatever);
$also_a_var2 = array(also_a_var);
$my_merged = array_merge(whatever2,also_a_var2);

[DeanWhitehouse]

Do you mean

$var1 ="one";

$var2 = "two";

$var3= $var1." ".$var2;

echo $var3;//prints one two

or do you mean

$var1 ="hello";

$var1 .= " world";

echo $var1; //prints hello world

[samoi]

I'm sorry, I think I didn't delievered the question very well.

 

ok I have this code: [which is for registration and so.]

 

<?php
$conn = mysql_connect("localhost", "root", "pass");
$db = mysql_select_db("d_base");

$username = $_POST['username'];
$pass = $_POST['password'];

if(some expression){
// do this
}
else{
// do this
}

echo $something_from_the_if_statement ;
?>

 

I'm sorry but I'm a beginner to the PHP. and I'm wondering if I can let this whole code execute by scripting only one var?

 

 

I'm sorry I really don't know how to explain and that's due my English is not my mother lang, and still a beginner to the PHP.

 

Thank you guys

[DeanWhitehouse]

Ok, i know its not your fault, but the question makes no sense, if i was you i would get it working and post any problems you have doing that.

[Barand]

In your example you could just do

 

$all_my_vars = $_POST;

 

Data posted from a form is always set except unset radio button and checkbox values. It may be empty though.

[samoi]

to be more clear

 

as of the example in my second reply, can I do like this?

 

$merge = array_this(conn, db, username, pass);

 

is this right? or no?

[DeanWhitehouse]

Erm, so you want to merge them all together, then no that wouldn't be usable then. So as i said, just keep it simple for now until you have a better understanding.

[samoi]

to be more clear

 

as of the example in my second reply, can I do like this?

 

$merge = array_this(conn, db, username, pass);

 

is this right? or no?

 

Guys, I'm just asking and wondering if that's possible!

 

I know I can just include this code or require it. but I'm wondering if I can collect all of these vars and put them all in only one var and let it execute itself

[samoi]

Erm, so you want to merge them all together, then no that wouldn't be usable then. So as i said, just keep it simple for now until you have a better understanding.

 

 

thank you man, but as I said I need an explanation why I can't do it?

is it because I can't array a function? what do you think?

[DeanWhitehouse]

Then no, you can't if you use it for the connection. You can merge them together then split them into separate vars.

But if you join them it will be like

$var1 = "hostusernamepassword";

mysql_connect($var1);// which will look like mysql_connect("hostusernamepassword"); which is missing two params

[champoi]

you can do it like this:

$the_array = array();

$the_array[] = "localhost";
$the_array[] = "bla bla";
$the_array[] = $something;

like that, but doing it in this order is usually for a set of information that has no need for signatures or labels. you cant use this like this:

$the_array[] = "localhost";
$the_array[] = "root";
$the_array[] = "root";

$conn = mysql_connect($the_array)

you should be doing this instead:

$the_array['a'] = "localhost";
$the_array['b'] = "root";
$the_array['c'] = "root";

$conn = mysql_connect($the_array['a'],$the_array['b'],$the_array['c'])

[DeanWhitehouse]

I don't think this works

$the_array[] = "localhost";
$the_array[] = "root";
$the_array[] = "root";

$conn = mysql_connect($the_array)

Because it will do

$conn = mysql_connect(array(3)) // or something like this.

[champoi]

I don't think this works

$the_array[] = "localhost";
$the_array[] = "root";
$the_array[] = "root";

$conn = mysql_connect($the_array)

Because it will do

$conn = mysql_connect(array(3)) // or something like this.

 

yup, that's what i said... you cant use it like that... i haven't tried it, but i just know it wouldn't work 

[DeanWhitehouse]

O' yer , sorry my bad, missed that line.

[wildboy211]

you could do this

 

$myarr = array("localhost","root","root");
$conn = mysql_connect($myarr[0],$myarr[1],myarr[2]);

[blueman378]

although why the hassle?

 

if its just for the database details why bother?

[DeanWhitehouse]

Exactly , you are just making it more hassle and more confusing for your self. Stay simple until you have a greater knowledge of PHP