[SOLVED] Shuffle()

[Michdd]

Why is this outputting the same thing everytime?

 

<?php

$arr = array('1','2');

echo shuffle($arr);

?>

 

It's outputting 1, everytime, is that the correct way to use it?

[DeanWhitehouse]

 

echo shuffle($arr[0]);

[Michdd]

Warning: shuffle() expects parameter 1 to be array, string given in /home/a3496022/public_html/shuffle.php on line 5

[DeanWhitehouse]

echo shuffle($arr[1]);

maybe?

Sorry i haven't used it before

Edit:

try

<?php

$arr = array('1','2');
$arr = shuffle($arr);
echo $arr[0];

?>

[Michdd]

echo shuffle($arr[1]);

maybe?

Sorry i haven't used it before

Edit:

try

<?php

$arr = array('1','2');
$arr = shuffle($arr);
echo $arr[0];

?>

 

First thing outputs the same error. Second thing echos nothing.

[wildteen88]

shuffle doesn't return anythink, accept true (or 1).

 

The way you use suffle is

$arr = range(0, 100);

echo 'Before<pre>' . print_r($arr, true) .'</pre>';

shuffle($arr);

echo 'After<pre>' . print_r($arr, true) .'</pre>';

[Mchl]

shuffle() indeed takes an array as an argument.

But I think you should randomize random seed before calling it. See how it's used in manual. See srand() function before shuffle() ?

 

And besides, echoing it, will always return 1 because it returns TRUE when it executes properly.

shuffle($arr);

means that $arr after that has been shuffled.

 

So

$arr = array("0","1","2","3");
shuffle($arr);
print_r($arr); //should print somewhat shuffled array

[Michdd]

I'm not actually looking for that, I'm looking for something that will give me a random thing from the array, I was pointed in the direction of shuffle() is this not good for it?

[wildteen88]

Look into http://uk.php.net/array_rand

[Michdd]

Look into http://uk.php.net/array_rand

Works good, just one more question, if I input things into the array more than once, that just gives it a higher probability of it being echoed, correct?

[DeanWhitehouse]

Yes