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john-formby

Open Search Results In A New Window

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Hi,

I have a search on my website which returns results based on the keywords row in my database. The link_text and url are displayed as hyperlinks to other websites. There is also a new_window row in the database table which is used to determine whether a link will be opened in the current or a new window; 0 = current, 1 = new. The problem is that I am not sure how to get the links to open in a new window.


Here is the database table:

[code]CREATE TABLE `links` (
  `link_id` int(11) NOT NULL auto_increment,
  `category_code` varchar(10) NOT NULL default '0',
  `link_text` varchar(254) NOT NULL default '',
  `url` varchar(254) NOT NULL default '',
  `description` text NOT NULL,
  `keywords` text NOT NULL,
  `time_added` timestamp(14) NOT NULL,
  `new_window` tinyint(4) NOT NULL default '0',
  PRIMARY KEY  (`link_id`)
) TYPE=MyISAM AUTO_INCREMENT=234;[/code]



Here is the search results processing and display:

[code]<?
//This is only displayed if they have submitted the form
if ($searching =="yes")
{

//If they did not enter a search term we give them an error
if ($find == "")
{
echo "<p>You forgot to enter a search term";
exit;
}

// Otherwise we connect to our Database
mysql_connect("localhost", "USER", "PASS") or die(mysql_error());
mysql_select_db("pagelinks") or die(mysql_error());

// We preform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);

//Now we search for our search term, in the field the user specified
$data = mysql_query("SELECT * FROM links WHERE keywords LIKE '%$find%'");

//And we display the results
while($result = mysql_fetch_array( $data ))
{

echo "<hr /><br />";
echo "<b><a href=\"".$result['url']."\">".$result['link_text']."</a></b>";
echo "<br />";
echo $result['description'];
echo "<br />";
echo "<a href=\"".$result['url']."\">".$result['url']."</a>";
echo "<br /><br />";  
}

echo "<hr /><br />";

//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches=mysql_num_rows($data);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query<br><br>";
}

//And we remind them what they searched for
echo "<b>Searched For:</b> " .$find;
}
?>[/code]


Thanks,

John

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Edit: I just read over your last post. Try the following for opening in self or new.

[code]echo "<hr /><br />";
if ($data['new_window'] == 1) {
  echo "<b><a href=\"".$result['url']."\" target=\"_new\">".$result['link_text']."</a></b>";
} else {
  echo "<b><a href=\"".$result['url']."\">".$result['link_text']."</a></b>"; #assumption that 'new_window' == 0 and open in self..
} [/code]

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what's not working john? have you viewed the outputted HTML to see if the HTML target information is being added to the hyperlinks? if not, then there's a problem with the my IF logic.

nm, found my problem:

[code]echo "<hr /><br />";
if ($result['new_window'] == 1) {
  echo "<b><a href=\"".$result['url']."\" target=\"_new\">".$result['link_text']."</a></b>";
} else {
  echo "<b><a href=\"".$result['url']."\">".$result['link_text']."</a></b>"; #assumption that 'new_window' == 0 and open in self..
} [/code]

i had $data in place of $result and i'm assuming that the $data var is actually your SQL syntax.

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