SUNIL16 Posted November 23, 2008 Share Posted November 23, 2008 Hi Friends, Below is my code for creating table mysql_query("CREATE TABLE `table1` ( `topicid` int(5) NOT NULL auto_increment, `topic` varchar(255) NOT NULL default'0', `detail` longtext NOT NULL, `memberid` int(5) NOT NULL default '0', `datetime` varchar(25) NOT NULL default'0', `view` int(4) NOT NULL default '0', `reply` int(4) NOT NULL default '0', PRIMARY KEY (`id`) ) TYPE=MyISAM AUTO_INCREMENT=1 "); mysql_query("CREATE TABLE `table2` ( `topics_id` int(4) NOT NULL default '0', `a_id` int(4) NOT NULL default '0', `a_memberid` int(5) NOT NULL default '0', `a_answer` longtext NOT NULL, `a_datetime` varchar(25) NOT NULL default '0', KEY `a_id` (`a_id`) ) TYPE=MyISAM;"); I able create only 2nd table... Please tell me y its not creating table1.. i am not getting where is the error... Link to comment https://forums.phpfreaks.com/topic/133904-creating-table/ Share on other sites More sharing options...
Mark Baker Posted November 23, 2008 Share Posted November 23, 2008 Try putting some traps for errors: <?php $result = mysql_query("CREATE TABLE `table1` ( `topicid` int(5) NOT NULL auto_increment, `topic` varchar(255) NOT NULL default'0', `detail` longtext NOT NULL, `memberid` int(5) NOT NULL default '0', `datetime` varchar(25) NOT NULL default'0', `view` int(4) NOT NULL default '0', `reply` int(4) NOT NULL default '0', PRIMARY KEY (`id`) ) TYPE=MyISAM AUTO_INCREMENT=1 "); if (!$result) { die('Invalid query: ' . mysql_error()); } $result = mysql_query("CREATE TABLE `table2` ( `topics_id` int(4) NOT NULL default '0', `a_id` int(4) NOT NULL default '0', `a_memberid` int(5) NOT NULL default '0', `a_answer` longtext NOT NULL, `a_datetime` varchar(25) NOT NULL default '0', KEY `a_id` (`a_id`) ) TYPE=MyISAM;"); if (!$result) { die('Invalid query: ' . mysql_error()); } ?> Link to comment https://forums.phpfreaks.com/topic/133904-creating-table/#findComment-697059 Share on other sites More sharing options...
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