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[SOLVED] Script Parsing Error


Akenatehm

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Hey Guys, the following script is showing up with this error:

Parse error: syntax error, unexpected ',' in /home/kaurlcom/public_html/relayadmin/add_user/add_user_test.php on line 41

 

in this script:

 

<?PHP 

include "connect.php"; 
// Checks the database for a user with a particular user name
$check = mysql_query("select ID from users where username='$username' limit 1;");
// get a row count of the number of rows found
if(mysql_num_rows($check) == 1) {  echo "Username Already In Use.";
} 
else { 

if(isset($_POST['submit']))

{

   $username=$_POST['username'];

   $password=$_POST['password'];
   
   $email=$_POST['email'];

   if(strlen($username)<1)

   {

      print "You did not enter a username.";

   }

   else if(strlen($password)<1)

   {

      print "You did not enter a password.";

   }

   else

   {

     $insert = "INSERT INTO `users` (username,password,email)",
mysql_real_escape_string($username),
mysql_real_escape_string($password),
mysql_real_escape_string($email));

      mysql_query($insert) or die("Could not insert comment" . mysql_error());
  
  echo "User Added. <A href''<a href=\"home.html\">Click here</a> To Go Home.";
   }

  }

?>

}
?>

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<?PHP

include "connect.php";
// Checks the database for a user with a particular user name
$check = mysql_query("select ID from users where username='$username' limit 1;");
// get a row count of the number of rows found
if(mysql_num_rows($check) == 1) {  echo "Username Already In Use.";
}
else {

if(isset($_POST['submit']))

{

   $username=$_POST['username'];

   $password=$_POST['password'];
   
   $email=$_POST['email'];

   if(strlen($username)<1)

   {

      print "You did not enter a username.";

   }

   else if(strlen($password)<1)

   {

      print "You did not enter a password.";

   }

   else

   {

     $insert = "INSERT INTO `users` (username,password,email) VALUES ('".mysql_real_escape_string($username)."','".mysql_real_escape_string($password)."','".mysql_real_escape_string($email)."'");
      mysql_query($insert) or die("Could not insert comment" . mysql_error());
         echo "User Added. <a href=\"home.html\">Click here</a> To Go Home.";
   }

  }

?>

}
?>

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     $insert = "INSERT INTO `users` (username,password,email)",
   mysql_real_escape_string($username),
   mysql_real_escape_string($password),
   mysql_real_escape_string($email));

 

You end the sql statement with the )", And that also caused a parse error because you are trying to connect strings using commas .

 

So fixed that, now the second error, a HTML one

     echo "User Added. <A href''<a href=\"home.html\">Click here</a> To Go Home.";

You have set the href attribute of the anchor as another anchor.

 

Edit: 3rd error i didn't see or fix

?>

}
?>

You end PHP so the last closing tag is printed as HTML not run as php.

 

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