[SOLVED] dont understand birthday script

[darkfreaks]

okay the problem i am having is that it is  subtracting a year somehwere so when it is sposed to read Age:1 it outputs age:0  ???

 

<?php
$months = array("", "January", "February", "March", "April", "May", "June", "July", "August", "Septemeber", "October", "November", "December");

$bdayMonth = $exBday[0];
if ($bdayMonth < 10) { $bdayMonth = ereg_replace("0", "", $bdayMonth); }

$exBday[0] = $months[$bdayMonth];

$birthday = "$exBday[0] $exBday[1], $exBday[2]";

$userAge = $this_year - $exBday[2];
if ($this_month < $exBday[0])
{
$userAge = $userAge - 1;
}
if (($this_month == $exBday[0]) AND ($today < $exBday[1]))
{
$userAge = $userAge - 1;
}
?>

[genericnumber1]

Well, one logical problem you have is that you're comparing $this_month (which I assume is an int) to $months[$bdayMonth] (which is a string). I haven't looked too much into it, so there may be other issues... but there are a lot of undefined variables in just what you've showed us.

[sKunKbad]

I played with your script, and here was the problem that I ran into:

 

where $this_month is compared to $exBday[0], $exBday[0] is a string which the value is a name of a month, like "June". You need to keep $exBday a number value if you want to compare these variables.

 

I admit, I had to add to your script just to figure this out. If you would supply more code I could probably come up with a solution. Here is what I was working with:

 

<?php
$exBday[0] = 6;
$exBday[1] = 28;
$exBday[2] = 2003;

$months = array("", "January", "February", "March", "April", "May", "June", "July", "August", "Septemeber", "October", "November", "December");

$bdayMonth = $exBday[0];
if ($bdayMonth < 10) { $bdayMonth = ereg_replace("0", "", $bdayMonth); }

$exBday[0] = $months[$bdayMonth];

$birthday = "$exBday[0] $exBday[1], $exBday[2]";

echo "<br>The birthday variable = " . $birthday;
$this_year = 2008;
$this_month = 5;

$userAge = $this_year - $exBday[2];

echo "<br>The variable userAge = " . $userAge;
if ($this_month < $exBday[0])
{
   $userAge = $userAge - 1;
}
if (($this_month == $exBday[0]) AND ($today < $exBday[1]))
{
   $userAge = $userAge - 1;
}
echo "<br>The variable userAge is now = " . $userAge;
?>

[darkfreaks]

Variables you need:

<?php

$this_month = date("n",$date);     // MONTH 1-12
$this_year = date("Y",$date);      // YEAR YYYY
$date = date("U"); // TIMESTAMP
$timestamp = $date;
?>

[sKunKbad]

Where does $date come from. When I run as-is, all I get is:

 

12 = this_month, and 1969 = this_year

[darkfreaks]

<?php

$date = date("U"); // TIMESTAMP
$timestamp = $date;?>

[sKunKbad]

THIS WORKS:

 

<?php
$exBday[0] = 11;
$exBday[1] = 29;
$exBday[2] = 2003;

$months = array("", "January", "February", "March", "April", "May", "June", "July", "August", "Septemeber", "October", "November", "December");

$bdayMonth = $exBday[0];
if ($bdayMonth < 10) { $bdayMonth = ereg_replace("0", "", $bdayMonth); }

$exBday2[0] = $months[$bdayMonth];

$birthday = "$exBday2[0] $exBday[1], $exBday[2]";

echo "<br>The birthday variable = " . $birthday;
$this_month = (int) date("n");     // MONTH 1-12
$this_year = (int) date("Y");      // YEAR YYYY
$today = (int) date("j");
echo "<br>$this_month = this_month, and $this_year = this_year, and today is $today";

$userAge = $this_year - $exBday[2];

echo "<br>The variable userAge = " . $userAge;
if ($this_month < $exBday[0])
{
   $userAge = $userAge - 1;
}
if (($this_month == $exBday[0]) && ($today < $exBday[1]))
{
   $userAge = $userAge - 1;
}
echo "<br>The variable userAge is now = " . $userAge;
?>