Php and mysql

[sridhar golyandla]

hi 2 all,

i am new to php and mysql...

please any body can help me out, egarly waiting for the solution...

 

how to active and deactivate the 2nd and 3rd dropdown boxes for selecting a particular first dropdown value. the 2nd and 3rd dropdowns are related to 1st dropdown and the values are posted from backend ie DB.

 

 

 

[The Little Guy]

Example JavaScript:

function seled(){
     var d1= document.getElementById("drop1");
     var d2= document.getElementById("drop2");
     var d3= document.getElementById("drop3");
     if(d1 != ''){
          d2.enabled = true;
          d3.enabled = true;
     }else{
          d2.enabled = false;
          d3.enabled = false;
     }
}

 

Example HTML:

<form action="javascript:void(0);" method="post">
<select onchange="seled()" id="drop1">
     <option value="">Select Value</option>
     <option value="1">1</option>
     <option value="2">2</option>
     <option value="3">3</option>
</select>
<select onchange="seled()" id="drop2">
     <option value="">Select Value</option>
     <option value="1">1</option>
     <option value="2">2</option>
     <option value="3">3</option>
</select>
<select onchange="seled()" id="drop3">
     <option value="">Select Value</option>
     <option value="1">1</option>
     <option value="2">2</option>
     <option value="3">3</option>
</select>
</form>