glenelkins Posted December 2, 2008 Share Posted December 2, 2008 Hi Im trying to detect upon click, if a checkbox is checked or unchecked, but my code isnt working :@ HTML: <input type="checkbox" id="editsection[]" name="editsection[]" onClick="show_amendment ( 1 );" /> 1 <input type="checkbox" id="editsection[]" name="editsection[]" onClick="show_amendment ( 2 );" /> 2 <input type="checkbox" id="editsection[]" name="editsection[]" onClick="show_amendment ( 3 );" /> 3 <input type="checkbox" id="editsection[]" name="editsection[]" onClick="show_amendment ( 4 );" /> 4 <input type="checkbox" id="editsection[]" name="editsection[]" onClick="show_amendment ( 5 );" /> 5 JavaScript function show_amendment ( id ) { /* IGNORE THESE 2 LINES THEY ARE FOR SOMETHING ELSE */ document.getElementById ( 'amendmentinstructions[' + id + ']' ).style.display = ''; document.getElementById ( 'instructions' ).style.display = ''; /*********************************************/ var ele = document.getElementById ( editsection[id] ); if ( ele.checked == true ) { alert ( "Checkbox " + id + " Is Checked" ); } } Quote Link to comment https://forums.phpfreaks.com/topic/135138-test-checkbox-status/ Share on other sites More sharing options...
KevinM1 Posted December 2, 2008 Share Posted December 2, 2008 The problem is that you're trying to use an id like a name. Remember: id's are UNIQUE. Each element with an id should have a unique id. So, try something like: HTML: <input type="checkbox" id="editsection[1]" name="editsection[]" onclick="show_amendment(1);" />1 JavaScript: function show_amendment(id) { var ele = document.getElementById('editsection[' + id + ']'); /* continue function */ } Quote Link to comment https://forums.phpfreaks.com/topic/135138-test-checkbox-status/#findComment-703859 Share on other sites More sharing options...
glenelkins Posted December 2, 2008 Author Share Posted December 2, 2008 ok ill give that a go. Remember: id's are UNIQUE. but the Ids should be unique as they are set as arrays with [] ?? Quote Link to comment https://forums.phpfreaks.com/topic/135138-test-checkbox-status/#findComment-703941 Share on other sites More sharing options...
KevinM1 Posted December 2, 2008 Share Posted December 2, 2008 ok ill give that a go. Remember: id's are UNIQUE. but the Ids should be unique as they are set as arrays with [] ?? They're not set, though, as your markup has all the elements having an id of editsection[]. Again, you're confusing names with ids. When you do something like this: var myCheckboxes = document.forms["myForm"].elements["editsection[]"]; You're accessing the checkboxes through their names and not their id's. And, in this example, all checkboxes with the name editsection[] are stored in the variable myCheckboxes as an array. Indeed, the same thing happens with PHP, which obtains $_GET and $_POST values by their names, and not their id's (which is why giving a group of checkboxes a name as an array works). Similarly, something like: var myCheckboxes = document.getElementById('editsection[]'); Obtains only one checkbox element - the first one. Why? Because all of the boxes have the same id, so the function stops at the first match. Try something like the following to see what I'm talking about in action: <html> <head> <title>Blah</title> <script type="text/javascript"> window.onload = function() { var myCheckboxes = document.forms["myForm"].elements["editsection[]"]; for(var i = 0; i < myCheckboxes.length; i++) { alert("Checkbox id: " + myCheckboxes[i].id); alert("Current checkbox: myCheckboxes[" + i + "]"); } } </script> </head> <body> <form name="myForm" action="#" method="post"> <input type="checkbox" id="editsection[]" name="editsection[]" /> 1 <input type="checkbox" id="editsection[]" name="editsection[]" /> 2 <input type="checkbox" id="editsection[]" name="editsection[]" /> 3 <input type="checkbox" id="editsection[]" name="editsection[]" /> 4 <input type="checkbox" id="editsection[]" name="editsection[]" /> 5 </form> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/135138-test-checkbox-status/#findComment-703998 Share on other sites More sharing options...
glenelkins Posted December 2, 2008 Author Share Posted December 2, 2008 ok i get what your saying. i didnt realise ids had to be completely unique...you learn something every day! heres another one for you. the following AJAX is fine in FF. There are 2 functions but only the get_document() one seems to work in IE, but both fine in FF: JAVASCRIPT function create_ajax_object() { // Create request object try { // Firefox etc ajaxObj = new XMLHttpRequest(); } catch ( e ) { // Ie try { ajaxObj = new ActiveXObject("Msxml2.XMLHTTP"); } catch ( e ) { try { ajaxObj = new ActiveXObject("Microsoft.XMLHTTP"); } catch ( e ) { alert ( "Your Browser Does Not Support AJAX! You Cannot Continue"); } } } return ( ajaxObj ); } function get_document ( doc_id ) { var ajaxObj = create_ajax_object(); if ( ajaxObj ) { ajaxObj.onreadystatechange = function() { if ( ajaxObj.readyState == '4' ) { var details = ajaxObj.responseText; details = details.split ( '&' ); document.getElementById ( 'documenttitle' ).innerHTML = details[0]; document.getElementById ( 'documentstyle' ).innerHTML = details[1]; document.getElementById ( 'documentpdf' ).innerHTML = details[2]; } } } ajaxObj.open ( 'GET', 'index.php?do=get_doc_info&id=' + doc_id, true ); ajaxObj.send( null ); } function get_address ( id, area ) { var ajaxObj = create_ajax_object(); if ( ajaxObj ) { ajaxObj.onreadystatechange = function() { if ( ajaxObj.readyState == '4' ) { var response = ajaxObj.responseText; var addressarea = document.getElementById ( 'deliveryaddress' + area ); response = response.split ( '&' ); addressarea.innerHTML = response[0] + '<br />' + response[1] + '<br />' + response[2] + '<br />' + response[3] + '<br /><br />Quantity to here: <input type="text" name="quantitytohere[]" value="" style="width: 40px;" />'; } } } ajaxObj.open ( 'GET', 'index.php?do=get_address&id=' + id, true ); ajaxObj.send ( null ); } HTML Code Of The get_address Call <div style="float: left; width: 229px;"> <div><strong>Delivery Address 1: </strong><select style="width: 80px;" name="deliveryaddress1" onChange="get_address ( this.options[this.selectedIndex].value, 1 );" /><option value="0">Please Select...</option>{offices}</select></div> <div style="margin-top: 15px;" id="deliveryaddress1"></div> </div> <div style="float: left; width: 233px;"> <div><strong>Delivery Address 2: </strong><select style="width: 80px;" name="deliveryaddress2" onChange="get_address ( this.options[this.selectedIndex].value, 2 );" /><option value="0">Please Select...</option>{offices}</select></div> <div style="margin-top: 15px;" id="deliveryaddress2"></div> </div> <div style="float: left; width: 235px;"> <div><strong>Delivery Address 3: </strong><select style="width: 80px;" name="deliveryaddress3" onChange="get_address ( this.options[this.selectedIndex].value, 3 );" /><option value="0">Please Select...</option>{offices}</select></div> <div style="margin-top: 15px;" id="deliveryaddress3"></div> </div> <div style="clear: both;"></div> Quote Link to comment https://forums.phpfreaks.com/topic/135138-test-checkbox-status/#findComment-704032 Share on other sites More sharing options...
KevinM1 Posted December 2, 2008 Share Posted December 2, 2008 Hmm...I'm not sure why it'd choke in IE. Nothing jumps out at me, although I must confess that when I have to use AJAX, I tend to rely on jQuery to do most of the heavy lifting for me. It saves on a ton of code, and just plain works. Quote Link to comment https://forums.phpfreaks.com/topic/135138-test-checkbox-status/#findComment-704294 Share on other sites More sharing options...
glenelkins Posted December 2, 2008 Author Share Posted December 2, 2008 why didnt i think of that? lol iv used jQuery for a few things. cheers Quote Link to comment https://forums.phpfreaks.com/topic/135138-test-checkbox-status/#findComment-704323 Share on other sites More sharing options...
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