small loop, dont have time to code it.

[sahel]

Hi,

 

If someone could plz code this small php code for me.

 

I have 4 variables to represent a startdate and enddate based on month and year.

 

php Code:

 

$startmonth = 3;
$startyear = 2007;
$endmonth = 5;
$endyear = 2008;

 

 

I want to loop through all months from 3-2007 to 5-2008 and do some processing for each month. Can anyone help me?

Just make me the loop and ill code the process inside the loop myself.

 

Thanks in advance.

[Mark Baker]

So you don't have time to write these five lines:

$startDate = mktime(0,0,0,$startmonth,1,$startyear);
$endDate = mktime(0,0,0,$endmonth+1,1,$endyear);
for($date = $startDate; $date < $endDate; $date = strtotime('+1 month',$date)) {
echo 'Date is '.date('M-Y',$date).'<br />';
}

I don't know how you're going to find time to write the actual processing for each month

[sahel]

Well, i did actually get time to write it.. but it was way more that what you sent..

 

$startmonth = 12;
$startyear = 2007;
$endmonth = 11;
$endyear = 2010;
$completedyear = 0;

for ($i = $startyear ; $i <= $endyear; $i++){
if($i < $endyear){$tendmonth=12;} else {$tendmonth=$endmonth;}
if($completedyear == 1) {$tstartmonth=1;} else {$tstartmonth=$startmonth;}
for ($x = $tstartmonth; $x <= $tendmonth; $x++){
	echo $i."-".$x."<br/>";
	$completedyear = 1;
}
}

 

I guess you have much better php skills than i have

[sasa]

try

$startmonth = 12;
$startyear = 2007;
$endmonth = 11;
$endyear = 2010;
$completedyear = 0;

for ($i = $startyear *12 + startmont; $i <= $endyear *12 + $endmonth; $i++){
   echo $i % 12, '-', (int) ($i / 12);
}