DamienRoche Posted December 14, 2008 Share Posted December 14, 2008 I have a simple array which will no doubt contain duplicates from time to time. It is within an if statement inside a function.... so, basically, I have: foreach($arr as $var){ echo "$var"; } What I want to do is have somekind of check to make sure I haven't already echoed the same var. An easier way would be to remove the duplicates first. How can I do this? I've tried array_unique($arr) before the foreach but isn't working so I must be missing something.. Anyone care to chip in? Thanks. Link to comment https://forums.phpfreaks.com/topic/136924-solved-foreach-with-arraybut-dont-show-duplicates/ Share on other sites More sharing options...
sasa Posted December 14, 2008 Share Posted December 14, 2008 <?php $arr = array(1,2,1,3,2,1,4,3,5); $arr = array_unique($arr); foreach ($arr as $v){ echo $v,"<br />\n"; } ?> Link to comment https://forums.phpfreaks.com/topic/136924-solved-foreach-with-arraybut-dont-show-duplicates/#findComment-715079 Share on other sites More sharing options...
Mark Baker Posted December 14, 2008 Share Posted December 14, 2008 Is your array just a simple array, e.g. $arr = array(1,3,5,2,4,6,1,5) or is it a more complex multi-dimensional array, e.g. $arr = array( 0 => array(1,2), 1 => array('sales',4)); Link to comment https://forums.phpfreaks.com/topic/136924-solved-foreach-with-arraybut-dont-show-duplicates/#findComment-715083 Share on other sites More sharing options...
DamienRoche Posted December 14, 2008 Author Share Posted December 14, 2008 Thanks for the help guys..I sussed out I should have run it through a variable. Thankfully, Mark, it's a simple array. Those multidimensional arrays are horrific. To me at least. Thanks again. Link to comment https://forums.phpfreaks.com/topic/136924-solved-foreach-with-arraybut-dont-show-duplicates/#findComment-715087 Share on other sites More sharing options...
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