lookee Posted December 15, 2008 Share Posted December 15, 2008 Below is my complete code (less the connection to the database) When I run the following code, I get the following error: Call to a member function fetch() on a non-object in line 138 If I comment out the PROBLEM LINES, the shopping cart partially displays onscreen, but the content of shopping cart passed from the previous .php screen is not passed in completion. What I need are the mysql commands or something to replace PROBLEM LINES that will access the information passed from the previous shopping cart page. Any help would be greatly appreciated. Thanks! // Select the Database $db_select=mysql_select_db($db_name); if (!$db_select) { die ("Couldn't select the database: <br/>". mysql_eror()); } // Process actions $cart = $_SESSION['cart']; $action = $_GET['action']; switch ($action) { case 'add': if ($cart) { $cart .= ','.$_GET['id']; } else { $cart = $_GET['id']; } break; case 'delete': if ($cart) { $items = explode(',',$cart); $newcart = ''; foreach ($items as $item) { if ($_GET['id'] != $item) { if ($newcart != '') { $newcart .= ','.$item; } else { $newcart = $item; } } } $cart = $newcart; } break; case 'update': if ($cart) { $newcart = ''; foreach ($_POST as $key=>$value) { if (stristr($key,'qty')) { $id = str_replace('qty','',$key); $items = ($newcart != '') ? explode(',',$newcart) : explode(',',$cart); $newcart = ''; foreach ($items as $item) { if ($id != $item) { if ($newcart != '') { $newcart .= ','.$item; } else { $newcart = $item; } } } for ($i=1;$i<=$value;$i++) { if ($newcart != '') { $newcart .= ','.$id; } else { $newcart = $id; } } } } } $cart = $newcart; break; } $_SESSION['cart'] = $cart; ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>Shopper Shopper</title> <link rel="stylesheet" href="css/styles.css" /> </head> <body> <div id="shopper"> <h1>Deliva's Shopping Cart</h1> <?php function writeShoppingCart() { $cart = $_SESSION['cart']; if (!$cart) { return '<p>You have no items in your shopping cart</p>'; } else { // Parse the cart session variable $items = explode(',',$cart); $s = (count($items) > 1) ? 's':''; return '<p>You have <a href="cart.php">'.count($items).' item'.$s.' in your shopping cart</a></p>'; } } echo writeShoppingCart(); ?> </div> <div id="contents"> <h1>Review Quantityh1> <?php function showCart() { global $db; $cart = $_SESSION['cart']; if ($cart) { $items = explode(',',$cart); $contents = array(); foreach ($items as $item) { $contents[$item] = (isset($contents[$item])) ? $contents[$item] + 1 : 1; } $output[] = '<form action="cart.php?action=update" method="post" id="cart">'; $output[] = '<table>'; foreach ($contents as $id=>$qty) { PROBLEM LINE ----> $row = $result->fetch(); PROBLEM LINE ----> extract($row); $output[] = '<tr>'; $output[] = '<td><a href="cart.php?action=delete&id='.$id.'" class="r">Remove</a></td>'; $output[] = '<td>'.$title.' by '.$author.'</td>'; $output[] = '<td>£'.$price.'</td>'; $output[] = '<td><input type="text" name="qty'.$id.'" value="'.$qty.'" size="3" maxlength="3" /></td>'; $output[] = '<td>£'.($price * $qty).'</td>'; $total += $price * $qty; $output[] = '</tr>'; } $output[] = '</table>'; $output[] = '<p>Grand total: <strong>£'.$total.'</strong></p>'; $output[] = '<div><button type="submit">Update cart</button></div>'; $output[] = '</form>'; } else { $output[] = '<p>You shopping cart is empty.</p>'; } return join('',$output); } echo showCart(); ?> Quote Link to comment https://forums.phpfreaks.com/topic/137000-call-to-a-member-function-fetch-on-a-non-object/ Share on other sites More sharing options...
xtopolis Posted December 15, 2008 Share Posted December 15, 2008 I don't see where $result is being defined anywhere in this script.. other than when you try to fetch(). Did you forget to query the database first? Quote Link to comment https://forums.phpfreaks.com/topic/137000-call-to-a-member-function-fetch-on-a-non-object/#findComment-715585 Share on other sites More sharing options...
lookee Posted December 15, 2008 Author Share Posted December 15, 2008 Okay, thanks... I now defined $result in the line above, and I call the function fetch several lines above, but I still get the error.. Fatal error: Call to a member function fetch() on a non-object Is the non-object $row, or is the non-object something in the database? My head hurts. Thanks for any help. <?php function writeShoppingCart() { $cart = $_SESSION['cart']; if (!$cart) { return '<p>You have no items in your shopping cart</p>'; } else { // Parse the cart session variable $items = explode(',',$cart); $s = (count($items) > 1) ? 's':''; return '<p>You have <a href="cart.php">'.count($items).' item'.$s.' in your shopping cart</a></p>'; } } echo writeShoppingCart(); ?> </div> <div id="contents"> <h1>REVIEW QUANTITY</h1> <?php * Checks for MySQL errors * @return boolean * @access public */ function isError () { if ( $this->connectError ) return true; $error=mysql_error ($this->dbConn); if ( empty ($error) ) return false; else return true; } /** * Returns an instance of MySQLResult to fetch rows with * @param $sql string the database query to run * @return MySQLResult * @access public */ function query($sql) { if (!$queryResource=mysql_query($sql,$this->dbConn)) trigger_error ('Query failed: '.mysql_error($this->dbConn). ' SQL: '.$sql); return new MySQLResult($this,$queryResource); } } /** * MySQLResult Data Fetching Class * @access public * @package SPLIB */ class MySQLResult { /** * Instance of MySQL providing database connection * @access private * @var MySQL */ var $mysql; /** * Query resource * @access private * @var resource */ var $query; /** * MySQLResult constructor * @param object mysql (instance of MySQL class) * @param resource query (MySQL query resource) * @access public */ function MySQLResult(& $mysql,$query) { $this->mysql=& $mysql; $this->query=$query; } /** * Returns the number of rows selected * @return int * @access public */ function size () { return mysql_num_rows($this->query); } /** * Returns the ID of the last row inserted * @return int * @access public */ function insertID () { return mysql_insert_id($this->mysql->dbConn); } /** * Checks for MySQL errors * @return boolean * @access public */ function isError () { return $this->mysql->isError(); } } /** * Fetches a row from the result * @return array * @access public */ function fetch () { if ( $row=mysql_fetch_array($this->query,MYSQL_ASSOC) ) { return $row; } else if ( $this->size() > 0 ) { mysql_data_seek($this->query,0); return false; } else { return false; } } // $result = mysql_query($query); function showCart() { global $db; $cart = $_SESSION['cart']; if ($cart) { $items = explode(',',$cart); $contents = array(); foreach ($items as $item) { $contents[$item] = (isset($contents[$item])) ? $contents[$item] + 1 : 1; } $output[] = '<form action="cart.php?action=update" method="post" id="cart">'; $output[] = '<table>'; foreach ($contents as $id=>$qty) { $sql = 'SELECT * FROM packages WHERE id = '.$id; $result = mysql_query($sql); PROBLEM LINE ---> $row = $result->fetch(); extract($row); $output[] = '<tr>'; $output[] = '<td><a href="cart.php?action=delete&id='.$id.'" class="r">Remove</a></td>'; $output[] = '<td>'.$title.' by '.$author.'</td>'; $output[] = '<td>£'.$price.'</td>'; $output[] = '<td><input type="text" name="qty'.$id.'" value="'.$qty.'" size="3" maxlength="3" /></td>'; $output[] = '<td>£'.($price * $qty).'</td>'; $total += $price * $qty; $output[] = '</tr>'; } $output[] = '</table>'; $output[] = '<p>Grand total: <strong>£'.$total.'</strong></p>'; $output[] = '<div><button type="submit">Update cart</button></div>'; $output[] = '</form>'; } else { $output[] = '<p>You shopping cart is empty.</p>'; } return join('',$output); } echo showCart(); ?> [\code] Quote Link to comment https://forums.phpfreaks.com/topic/137000-call-to-a-member-function-fetch-on-a-non-object/#findComment-715725 Share on other sites More sharing options...
lookee Posted December 15, 2008 Author Share Posted December 15, 2008 I have this shopping cart almost running, but it doesn't display the actual names of the contents within the database. I've indicated below where I'm having problems ... What code do I insert to display the database contents of the related Ids? I have tried a variety of things, but none are working. Any help would be greatly appreciated. function connectToDb () -- specifics removed.... // Select the Database $db_select=mysql_select_db($db_name); if (!$db_select) { die ("Couldn't select the database: <br/>". mysql_eror()); } function isError () { if ( $this->connectError ) return true; $error=mysql_error ($this->dbConn); if ( empty ($error) ) return false; else return true; } /** * Returns an instance of MySQLResult to fetch rows with * @param $sql string the database query to run * @return MySQLResult * @access public */ function query($sql) { if (!$queryResource=mysql_query($sql,$this->dbConn)) trigger_error ('Query failed: '.mysql_error($this->dbConn). ' SQL: '.$sql); return new MySQLResult($this,$queryResource); } } /** * MySQLResult Data Fetching Class * @access public * @package SPLIB */ class MySQLResult { /** * Instance of MySQL providing database connection * @access private * @var MySQL */ var $mysql; /** * Query resource * @access private * @var resource */ var $query; /** * MySQLResult constructor * @param object mysql (instance of MySQL class) * @param resource query (MySQL query resource) * @access public */ function MySQLResult(& $mysql,$query) { $this->mysql=& $mysql; $this->query=$query; } /** * Returns the number of rows selected * @return int * @access public */ function size () { return mysql_num_rows($this->query); } /** * Returns the ID of the last row inserted * @return int * @access public */ function insertID () { return mysql_insert_id($this->mysql->dbConn); } /** * Checks for MySQL errors * @return boolean * @access public */ function isError () { return $this->mysql->isError(); } } /** * Fetches a row from the result * @return array * @access public */ function fetch () { if ( $row=mysql_fetch_array($this->query,MYSQL_ASSOC) ) { return $row; } else if ( $this->size() > 0 ) { mysql_data_seek($this->query,0); return false; } else { return false; } } $result = mysql_query($sql); // $result = mysql_query($query); function showCart() { $cart = $_SESSION['cart']; if ($cart) { $items = explode(',',$cart); $contents = array(); foreach ($items as $item) { $contents[$item] = (isset($contents[$item])) ? $contents[$item] + 1 : 1; } NOT SURE WHAT TO PUT HERE TO SHOW CONTENTS.... $output[] = '<form action="cart.php?action=update" method="post" id="cart">'; $output[] = '<table>'; foreach ($contents as $id=>$qty) { $sql = 'SELECT * FROM packages WHERE id = '.$id; $result = mysql_query($sql); $output[] = '<tr>'; $output[] = '<td><a href="cart.php?action=delete&id='.$id.'" class="r">Remove</a></td>'; $output[] = '<td>'.$size.' by '.$width.'</td>'; $output[] = '<td>£'.$price.'</td>'; $output[] = '<td><input type="text" name="qty'.$id.'" value="'.$qty.'" size="3" maxlength="3" /></td>'; $output[] = '<td>£'.($price * $qty).'</td>'; $total += $price * $qty; $output[] = '</tr>'; } $output[] = '</table>'; $output[] = '<p>Grand total: <strong>£'.$total.'</strong></p>'; $output[] = '<div><button type="submit">Update cart</button></div>'; $output[] = '</form>'; } else { $output[] = '<p>You shopping cart is empty.</p>'; } return join('',$output); } echo showCart(); ?> Thanks! Quote Link to comment https://forums.phpfreaks.com/topic/137000-call-to-a-member-function-fetch-on-a-non-object/#findComment-715898 Share on other sites More sharing options...
fenway Posted December 15, 2008 Share Posted December 15, 2008 Impossible to debug this way... this is a magic object class. Quote Link to comment https://forums.phpfreaks.com/topic/137000-call-to-a-member-function-fetch-on-a-non-object/#findComment-716005 Share on other sites More sharing options...
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