anthony-needs-you Posted December 19, 2008 Share Posted December 19, 2008 Can somebody help me to know where to put this mysql_query("SELECT * FROM test WHERE expireDate > CURDATE()"); into this $query = "SELECT id, destination, airport, resort, hotel, board, duration, departureDate, expireDate, price, description, stars, customerRef FROM test ORDER BY price"; $result = mysql_query($query) or die('Error : ' . mysql_error()); while(list($id, $destination, $airport, $resort, $hotel, $board, $duration, $departureDate, $expireDate, $price, $description, $stars, $customerRef) = mysql_fetch_array($result, MYSQL_NUM)) { Thanks everyone Link to comment https://forums.phpfreaks.com/topic/137679-solved-php-mysql_query/ Share on other sites More sharing options...
JonnoTheDev Posted December 19, 2008 Share Posted December 19, 2008 Take the query string out of the mysql_query() function and put it into the $query variable replacing the old query: $query = "SELECT * FROM test WHERE expireDate > CURDATE()"; Link to comment https://forums.phpfreaks.com/topic/137679-solved-php-mysql_query/#findComment-719551 Share on other sites More sharing options...
anthony-needs-you Posted December 19, 2008 Author Share Posted December 19, 2008 Cheers have followed your instruction and it works! Thanks a lot! $query = "SELECT id, destination, airport, resort, hotel, board, duration, departureDate, expireDate, price, description, stars, customerRef FROM test WHERE expireDate > CURDATE()";[code] Link to comment https://forums.phpfreaks.com/topic/137679-solved-php-mysql_query/#findComment-719554 Share on other sites More sharing options...
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