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how to display the data had by a html form, in a div in the same page?

it works!!!

By it works!!!
in PHP Coding Help

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it works!!! Newbie

it works!!!

Posted
Posted

After posting  the selected category and the subcategory the names of respective objects from the DATABASE in div "objects" ne the same page with the form that has this layout:

html_form.png

 

this is the php code:

 

<?php

include("dbinfo.php");

$connection = mysql_connect("server",$username,$password);

if (!$connection) {

die('Not connected : ' . mysql_error());

}

$db_selected = mysql_select_db($database, $connection);

if (!$db_selected) {

die ('Can\'t use db : ' . mysql_error());

}

$result1=mysql_query("Select idg from Grupimi where grupim='$_POST[category]' and detaje='$_POST[subcategory]'") or die(mysql_error()); 

$row1 = mysql_fetch_array($result1);

$klasifikimi = $row1['idg'];

$result2=mysql_query("Select oemer from Objekt where klasifikimi='$klasifikimi'") or die(mysql_error()); 

<?

}else{

while($row2 = mysql_fetch_array($result2)){

  echo $row2['oemer'];

  echo "<br/>";

}

}

mysql_close($connection);

?>

Yesideez Advanced Member

Yesideez

Posted
Posted

OK where's the PHP code - that's just the HTML?

 

You can do what I do and incorporate your PHP and HTML into one page - here's an example...

<?php
  $strName=$_POST['name'];
  if ($_POST['subshow']) {
    //user clicked submit so validate here
  }
?>
<html>
<head>
  <title>My Page</title>
</head>
<body>
  <form action="<?=$_SERVER['PHP_SELF']?>" method="post">
    Name: <input type="text" name="name" value="<?=$strName?>" /><br />
    <input type="submit" name="subshow" value="Show Data" />
  </form>
  You entered: <?=$strName?>
</body>
</html>

 

EDIT: When showing data inside a textbox do it like this:

<textarea name="mytextbox" cols="40" rows="7"><?=$txtSomeText?></textarea>

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