ondi Posted December 29, 2008 Share Posted December 29, 2008 Hi, here's my code, and things are working as they should. My only problem is I can't seem to move my drop-down list from the cell it is in to the cell left one. (see photo) Can anyone see from my code whats going wrong? Site url: http://www.walthamforest-fc.co.uk/stats/newplayer.php?id=3 <TABLE WIDTH="520" ALIGN=center BORDER=0 CELLSPACING=0 CELLPADDING=0> <TR VALIGN=middle ALIGN=center> <td><img src="http://www.walthamforest-fc.co.uk/stats/images/playerbar.jpg"></TD> </TR> <tr VALIGN=left ALIGN=center> <td><img src=" <?php echo $image_url = "images/" . $playerdata['id'] . "_1.jpg"; ?>"/><img src=" <?php echo $image_url = "images/" . $playerdata['id'] . ".jpg"; ?>"/> </td></tr> <tr> <td background="/stats/images/playernameback.jpg" width="308" height="46"> <font face="Arial" size="4"><span style="letter-spacing: 0pt"><font color="#018609"> <?php echo "$playerdata[firstname]" ?> <?php echo "$playerdata[lastname]" ?> </TD> <td> <td background="/stats/images/playernameback.jpg" width="202" height="46"><?php // //Haetaan kaikki pelaajat dropdownia varten // $sql = ' SELECT P.PlayerID AS id, P.PlayerLastName AS lastname, P.PlayerFirstName AS firstname, P.PlayerPublish AS publish FROM tplss_seasons S LEFT OUTER JOIN tplss_players P ON P.PlayerID = S.SeasonPlayerID '; if($defaultseasonid == 0) { $sql .= " WHERE P.PlayerID != '' AND P.PlayerPublish = '1' GROUP BY id ORDER BY firstname, lastname"; } else { $sql .= " AND S.SeasonID = '$defaultseasonid' WHERE P.PlayerID != '' AND P.PlayerPublish = '1' GROUP BY id ORDER BY firstname, lastname"; } $query = mysql_query("$sql", $connection) or die(mysql_error()); echo"<select name=\"playerid\">"; while($data = mysql_fetch_array($query)) { if($data['id'] == $id) { echo"<option value=\"$data[id]\" SELECTED>$data[firstname] $data[lastname]</option>\n"; } else { echo"<option value=\"$data[id]\">$data[firstname] $data[lastname]</option>\n"; } } echo"</select> <input type=\"submit\" name=\"change_player\" value=\"$txt_change\">"; mysql_free_result($query); $ttl = (($_SESSION['getAdditional'] + 1) % 2) ? "Show": "Hide"; ?> </td> </tr> Link to comment https://forums.phpfreaks.com/topic/138735-problems-with-table-cells/ Share on other sites More sharing options...
ToonMariner Posted January 1, 2009 Share Posted January 1, 2009 OK - using tables for layout is the old school method and I find it impossible to 'help' people with problems with table based layouts - I don't believe it helps anybody... this applies to you too - I will however point you to using some markup validation - that wlll help initially. Link to comment https://forums.phpfreaks.com/topic/138735-problems-with-table-cells/#findComment-727394 Share on other sites More sharing options...
htmlstig Posted January 1, 2009 Share Posted January 1, 2009 </TD> <td> <td background="/stats/images/playernameback.jpg" width="202" height="46"><?php is that <td> needed as there is no closing </td>? Link to comment https://forums.phpfreaks.com/topic/138735-problems-with-table-cells/#findComment-727615 Share on other sites More sharing options...
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