winnij Posted July 7, 2006 Share Posted July 7, 2006 Hello,For a website php and mysql are used. A recordset contains names and a filelocation.Each name an each fillelocation needs to become a variable. I would achieve that by a for loop, see example.for($i=0; $totalRows_RS-1 ; $i++){ ($tab +($i+1)) = $row_RS['name']; ($link + ($i+1)) = $row_RS['location'];}PHP returns Parse error: parse error, unexpected '='..Has anyone an idea to solve this problem? Quote Link to comment https://forums.phpfreaks.com/topic/13929-generate-variable-name/ Share on other sites More sharing options...
Zane Posted July 7, 2006 Share Posted July 7, 2006 because you're using the wrong syntaxdo this[code]${"tab".$i++} = $row_RS['name'];[/code] Quote Link to comment https://forums.phpfreaks.com/topic/13929-generate-variable-name/#findComment-54301 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.