php Date help needed

[jamez141]

Hello, i'm trying to write a script where the next sunday service is displayed on our church website homepage. I've come accross a problem where i can only get php to display a date 2 sundays from now or 3 sundays from now but i want to get the second sunday of the month.

- the output needs to just be a simple echo"";

- im guessing i need to then compare the 'next sunday' to a list of ifelse statements containing the first sunday

I hop you know what i mean.

Anyone know how i could do this?

 

thanks!

James.

[rhodesa]

here are the basics for what you need:

<?php
  $time = mktime(0,0,0,1,1,2009); //Starting point...this for instance is January 1st, 2009
  $sunday = strtotime("Sunday",$time); //Get's the following sunday (if the starting point IS a sunday, it will return the same day)
  print date('r',$sunday); //Print out the date
?>

 

edit: to find the second, third, etc sunday, just adjust the starting point to seven days later:

<?php
  $time = mktime(0,0,0,1,8,2009); //Starting point...one week in (aka we will find the second sunday)
  $sunday = strtotime("Sunday",$time);
  print date('r',$sunday);
?>

[jamez141]

Ok, thanks! i think i can make this work.

We have the same services every second, forth and fifth sunday and another on first and a different one on the third. (it gets confusing )

is there a way to just automate this without me going through every month and typing it in?

 

ta,

James.

[rhodesa]

try this out. it will do it for the current month. depending on how you control which month is shown, you can make that part dynamic too

 

<?php
  $month = date('m');
  $year = date('Y');
  $time = strtotime("Sunday",mktime(0,0,0,$month,1,$year));
  for($week = 1;date('m',$time) == $month && date('Y',$time) == $year;$week++){
    switch($week){
      case 2:
      case 4:
      case 5:
        print "This part is for the 2nd, 4th, and 5th weeks. The date here is: ".date('r',$time)."<br>";
        break;
      case 1:
        print "This part is for the 1st week. The date here is: ".date('r',$time)."<br>";
        break;
      case 3:
        print "This part is for the 3rd week. The date here is: ".date('r',$time)."<br>";
        break;
    }
    $time = strtotime('+7 days',$time);
  }
?>

[jamez141]

Hi, thanks for your help so far..

so i have this at the moment...

<?php
  $month = date('m');
  $year = date('Y');
  $time = strtotime("Sunday",mktime(0,0,0,$month,1,$year));
  for($week = 1;date('m',$time) == $month && date('Y',$time) == $year;$week++){
    switch($week){
      case 2:
      case 4:
      case 5:
        print "This part is for the 2nd, 4th, and 5th weeks. The date here is: ".date('F j, Y',$time)."<br>";
        break;
      case 1:
        print "This part is for the 1st week. The date here is: ".date('F j, Y',$time)."<br>";
        break;
      case 3:
        print "This part is for the 3rd week. The date here is: ".date('F j, Y',$time)."<br>";
        break;
    }
    $time = strtotime('+7 days',$time);
  }
?>

 

and this produces this...

 

This part is for the 1st week. The date here is: January 4, 2009

This part is for the 2nd, 4th, and 5th weeks. The date here is: January 11, 2009

This part is for the 3rd week. The date here is: January 18, 2009

This part is for the 2nd, 4th, and 5th weeks. The date here is: January 25, 2009

 

so it's showing me the dates of all the sundays in this month.

- can it display the current month where January is? i cant get this to work

- and how do you make it only display the next sunday?

 

Thanks!

J.

[DeanWhitehouse]

can it display the current month where January is? i cant get this to work

 

Huh?

[jamez141]

oh yeah.

urm.. haha

woops 

[DeanWhitehouse]

If you only want it to display the next sunday you can either limit the loop to 1 or not use a loop and do it manually

[rhodesa]

to display the current month, use the date() function:

print date('F');

 

if you just want the NEXT sunday:

  $this_sunday = strtotime("Sunday");
  $week = ceil(date('d',$this_sunday) / 7);
  print "This Sunday is on ".date('r',$this_sunday)." and is week $week";

[jamez141]

Aha! Hopefully this will work...

<?php
$this_sunday = strtotime("Sunday");
  $week = ceil(date('d',$this_sunday) / 7);
  print "This Sunday is on ".date('r',$this_sunday)." and is week $week";
  echo"<br><br>";
  if ($week == "1"){print "This sunday there is a Family service starting at 10:30 Click here for more";}
  elseif ($week == "2"){print "This sunday there is Come Together and Get Together.";}
  elseif ($week == "3"){print "This Sunday there is Praise Together.";}
  elseif ($week == "4"){print "This sunday there is Come Together and Get Together.";}
  elseif ($week == "5"){print "This sunday there is Come Together and Get Together.";}
  

 

Thanks for you help!

J.