trying to access variables that are inside a function...

[dottedquad]

function code:
[code]  function chk_member()
  {
   
$location = "localhost";
    $username = "root";
    $password = "2dollarbill";
    $database = "gold";

$conn = mysql_connect($location, $username, $password);
    if (!$conn) { die ("Could not connect to MySQL"); }
mysql_select_db($database,$conn) or die ("Could not open database");

$sql = mysql_query("SELECT `memid`, `fname`, `lname` FROM `membership` WHERE `memid` = 1234567891");
$row = mysql_fetch_row($sql);

$fname = $row[0];
$lname = $row[1];
$dob = $row[3];

}[/code]

How do I access $fname, $lname, and $dob outside of the chk_member function so I echo out the values of those variables?

[ShiVer]

I've always thought you chould just echo them. Can you not?

[dottedquad]

[quote author=ShiVer link=topic=99918.msg393790#msg393790 date=1152406386]
I've always thought you chould just echo them. Can you not?
[/quote]

Ya I can echo out the variables inside of the function, but i'm trying to echo them outside of the function.  It won't since i'm outside of the function scope.

[kenrbnsn]

You either have to return them back to the calling scope or declare them global inside your routine. I prefer to return them in an array:
[code]<?php
list ($fname, $lname, $dob) = chk_member();

  function chk_member()
  {
   
$location = "localhost";
    $username = "root";
    $password = "2dollarbill";
    $database = "gold";

$conn = mysql_connect($location, $username, $password);
    if (!$conn) { die ("Could not connect to MySQL"); }
mysql_select_db($database,$conn) or die ("Could not open database");

$sql = mysql_query("SELECT `memid`, `fname`, `lname` FROM `membership` WHERE `memid` = 1234567891");
$row = mysql_fetch_row($sql);
        return (array($row[0], $row[1], $row[3]));
}
?>[/code]

Ken

[dottedquad]

[quote author=kenrbnsn link=topic=99918.msg393801#msg393801 date=1152408061]
You either have to return them back to the calling scope or declare them global inside your routine. I prefer to return them in an array:
[code]<?php
list ($fname, $lname, $dob) = chk_member();

  function chk_member()
  {
   
$location = "localhost";
    $username = "root";
    $password = "2dollarbill";
    $database = "gold";

$conn = mysql_connect($location, $username, $password);
    if (!$conn) { die ("Could not connect to MySQL"); }
mysql_select_db($database,$conn) or die ("Could not open database");

$sql = mysql_query("SELECT `memid`, `fname`, `lname` FROM `membership` WHERE `memid` = 1234567891");
$row = mysql_fetch_row($sql);
        return (array($row[0], $row[1], $row[3]));
}
?>[/code]

Ken
[/quote]

sweet that works, is there any way I can break up the those variables to echo them out seperatly?