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Hi Everyone,

 

I am having trouble figuring out how to store data from my form into an array and reading it.  This is what I have so far. 

 

<?php
   echo "<form id='form1' name='form1' method='post' action=''><p>
         <label><input type='text' name='memberid[]' value='memberid' /></label></p><p>
     <label><input type='text' name='memberid[]' value='memberid' /></label></p><p>
         <label><input type='submit' name='submit'  value='Submit' /></label></p>
         </form>";

	 $memberid = array("$memberid");
   echo "output = " . print_r("$memberid");
?>
   

 

I get the following error:

 

Notice: Undefined variable: memberid in C:\Program Files\EasyPHP 2.0b1\www\test.php on line 8

Arrayoutput = 1

 

Thanks

 

Ralph

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https://forums.phpfreaks.com/topic/140842-storing-form-data-into-array/
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That method is usually used for checkboxes

<input type="checkbox" name="members[]" value="1" />Member 1
<input type="checkbox" name="members[]" value="2" />Member 2

 

Then AFTER YOU POST (submit the form) they are automatically in the $_POST['members'] array if any of them were checked, otherwise $_POST['members'] doesn't exist if none were checked.

 

To accomplish what I think you want to do, perhaps looking at this threads will help: http://www.phpfreaks.com/forums/index.php/topic,223358.0.html

That worked!!

 

Thank you guys for your help. 

 

xtopolis here is what I did to fix it from your example, I have been tryting to get this to work for a week!!

 

<?php
   echo "<form id='form1' name='form1' method='post' action=''><p>
         <label><input type='text' name='memberid[]' value='memberid' /></label></p><p>
     <label><input type='text' name='memberid[]' value='memberid' /></label></p><p>
         <label><input type='submit' name='submit'  value='Submit' /></label></p>
         </form>";

	 foreach($_POST['memberid'] as $value){
            echo "The value was $value<br />";
         }

?>

 

Thank you Daniel0 for the tutorial I will go through it.

 

 

 

 

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