SUBSTR not working with numbers

[affc]

Hello,

 

This code used to work by placing a "0" infront of a number if it was only between 1-9 it would make it 01-09. Now it simply puts a 1 infront of it so 11-19 which isn't what Im after. Was there a code upgrade I missed? Thanx in advance

 

$sql6="SELECT * FROM $tbl_name7";

$result6=mysql_query($sql6);

$count3=mysql_num_rows($result6);

$COUNTS =$count3+1;

$number=$_GET['No'];

$THISNUMBER = substr("$COUNTS".$number, -2);

[redarrow]

works lovely with numbers.

<?php

$num="1234567789";

echo " ".substr($num,0,2)."";

?>

 

<?php

$num['redarrow']="1234567789";

echo " ".substr($num['redarrow'],0,2)."";

?>

 

what the "" << for then?

 

[redarrow]

$THISNUMBER = substr("$COUNTS".$number, -2);

 

to

 

$THISNUMBER = substr($COUNTS.$number, -2);

 

and try agin.

 

works perfect.

<?php

$num['redarrow']="1234567789";
$add="910";

echo " ".substr($num['redarrow'].$add,-3)."";

?>

[affc]

Hi thank you for the replied but that doesn't work for what I am after.

 

I have a GET function that will get a number such as "1" from the address bar. I want to add a 0 at the beginning and so on up to 9 and any number after that is left alone but limited to only 2 digit numbers for the result. I cant seem to get it to put a 0 at the start anymore so 1 becomes 01 and so on.

[trq]

$sql6="SELECT * FROM $tbl_name7";
$result6=mysql_query($sql6);
$count3=mysql_num_rows($result6);
$COUNTS =$count3+1;
$number=$_GET['No'];
$THISNUMBER = sprintf("%02d", $number);

[affc]

Ah that works but I want it so that if there is no No in the Address bar it will use the $COUNT result instead? Is this possible, my script worked fine last year but this year seems not to be working.

[affc]

Ah using your Code I did get it to work. Just used this at the end of your code:

 

if(empty($number)){

$THISNUMBER=$COUNTS;

}

 

Works a charm thank you for your help