[SOLVED] function() question

[AV1611]

I have a function I wrote, but to make the point, here's a simple example.

 

Let's say I do

 

function myfunc($a,$b){

echo $a;

echo $b;

}

 

What I want to do is make $b optional, and if it's not set, for the function to assume a predefined string.  In this case it's a percentage that I use in some css later, so I want the string to default to 100 if $b is not used i.e. myfunc($a) but $b to pass if it's myfunc($a,$b)

 

How do I do that?

 

Thanks.

 

[genericnumber1]

Easy enough...

 

<?php
function myfunc($a,$b = '100'){
echo $a;
echo $b;
}

[AV1611]

Easy enough...

 

<?php
function myfunc($a,$b = '100'){
echo $a;
echo $b;
}

 

Thanks, I found that but it didn't make sense until you just did it   I also found this but it's more complex than I need in this case, but is a better answer maybe in some cases:

 

        $numArgs = func_num_args();

 

Thanks.

[genericnumber1]

Yes, PHP, like some other languages, supports variable number of arguments through the func_num_args and func_get_args functions. Very handy.

[allworknoplay]

Be careful with these built in functions such as func_num_args();

 

Because they allow a variety of different inputs so it could be a hassle to trouble issues if your program gets long and complicated.

 

The best way is what GenericNumber posted as his example.

 

Also, functions only accept scalar variables so don't get too carried away...