Jump to content

Recommended Posts

Hi all,

 

Wondering if someone could point out what I'm doing wrong,

 

Have 3 tables:

 

`states`

 

stateID

state

clientID

date

 

 

`states_info`

 

stateID

stateText

position

 

 

`clients`

 

clientID

clientName

 

 

`states_info` contains unique info about various states a client can be in, with position being the order they appear in. `states` list can contain multiple entries for a client detailing the state they were in and the date. What I'd like to do is pull out a count of the number of clients in each state.

 

If I use:

 

SELECT COUNT(s.clientID) AS noClients, st.state, st.stateID FROM `states_info` AS st LEFT JOIN `states` AS s ON st.stateID=s.state GROUP BY st.stateID
ORDER BY st.position ASC

 

it will produce a count, however includes all clients that have been in a state. What I'd like it to only include the latest state (ie, `states_info` position is the highest number) a client is in.

 

 

Then when I want to view a list of clients only in a certain state how I can get a list of clients in which the viewed state is the latest one (ie, the highest position number in `states_info`).

 

SELECT c.*, si.state FROM `clients` AS c LEFT JOIN `states` AS s ON s.clientID=c.clientID LEFT JOIN `states_info` AS si ON s.state=si.stateID WHERE s.state=$value

 

Works but not ignoring clients who are in a higher states_info position.

 

 

Thanks for any pointers.

Link to comment
https://forums.phpfreaks.com/topic/145277-incorrect-count-values-obtained/
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.