left shift operator

[allworknoplay]

Sorry for this dumb math question, but what is the answer to this?

 

 

$i = 16 << 4;

 

Is $i = 256?

 

I know that the left shift operator multiplies an integer by the powers of two and I have never been great at math...

 

 

[drisate]

lol you just need to echo $i bro and you will find out hehe

 

echo 16 << 4;

[allworknoplay]

lol you just need to echo $i bro and you will find out hehe

 

echo 16 << 4;

 

hahaha, I should have tried that, yes it is 256....I just want to make sure I get my facts straight, I'm

basically saying, 16 to the power of 2, four times?

 

16 * 2 = 32

32 * 2 = 64

64 * 2 = 128

128 * 2 = 256

 

 

[drisate]

Yeah :-)

And you can also use the pow(x,y) function to do that

[allworknoplay]

Yeah :-)

And you can also use the pow(x,y) function to do that

 

When I use that function, I get 65536 instead.

 

"pow(16x4)" VS "16 << 4"

 

So the first one, I think is doing 16x16x16x16 which gives me 65536...

 

The second one is 256...

 

 

[corbin]

Binary operators operate at a binary level (big surprise).

 

 

a << x = a * 2^x

 

 

On a binary level, let's say we have 5:

101

 

Now << 1 would add a 0 onto the end:

5 << 1 = 1010 = 10 (dec)

 

 

See how it works?

 

 

53 << 7 = 110101 0000000 = 7296