Get a Portion of a string

[RabPHP]

Greetings,

 

I have a variable that looks like "THISISSOME(2 EXTREMELY)RANDOMDATA12345AP" I need to strip out the random data and return everything after the first occurance of a number that is not inside a parenthesis.  In this example, I want to only get 12345AP.  The data may be random wordsand characters without a defined length.

 

This one has me baffled but I know it's possible, please advise!

 

Thanks

Rab

[farkewie]

s

<?php

$string = "THISISSOME(2 EXTREMELY)RANDOMDATA12345AP";
//get rid of everything before the ")"
$string = explode( ')', $string );
//Keep everything after the last ")"
$string = $string[count( $string ) - 1];
$strLen = strlen( $string );
$index = 0;
for ( $i = 0; $i < $strLen; $i++ )
{
if ( is_numeric($string[$i]) )
{

	//Grab where the numbers start
	$index = $i;
	//stop any more checks.
	$i = $strLen + 1;
}
}
//grab the string where the numbers start
$string = substr( $string, $index );
print $string;

// outputs 12345AP


?>

 

 

[corbin]

Depending on the complexity of your string, this might work a little better:

 

 

if(preg_match('~\([^\(]+\)([\d]+)~', $str, $m)) {

  echo $m[1];

}

[RabPHP]

Ok one more final addition.  Sometimes there is a number outside of the parenthesis, it's always either a 1 or a 2.  How do I strip off the first character if it's a 1 or 2?

 

Rab

[farkewie]

Is the number the next char after the parenthesis?

 

Your example string has a first number of a 1 if we were to srip the fist 1 you would lose part of your string.

[RabPHP]

Those portions of the string contining a 1 or a 2 are uniform, I simple did a str_replace before subjecting your code on the string and it resolved the problem.  Much appreciated!

 

Rab