[SOLVED] Problem with ECHO code

[raytri]

Hi. I'm a new member and pretty new to PHP. My apologies if this question has been answered a hundred times before:

 

When I write the following code:

 

echo '<tr><td><a href="javascript:PopupPic(\'../images/popups/landscapes/'$BigImage'\')"><img src="../images/landscapes/'$Image'" class="gallery" alt="'$Title'" /></a><br /><p class="title">'$Title'</p><p class="description">'$Width'” x '$Height'”</p><p class="sold">'$IsItSold'</p></td>';

 

I get the following error:

 

Parse error:  parse error, unexpected T_VARIABLE, expecting ',' or ';'

 

I can't spot the problem. I think I've properly escaped the single quotes in the echoed portion, and there's no missing bracket errors that I know of.

 

For what it's worth, here's the full code section. Note that the "elseif" and "else" echos are enclosed in double quotes (with double quotes escaped) rather than single quotes; I'm trying to fix the above coding problem before changing them.

 

while ($myrow = mysql_fetch_array ($result))

{

if ($column == 1)// first column display

{

echo '<tr><td><a href="javascript:PopupPic(\'../images/popups/landscapes/'$BigImage'\')"><img src="../images/landscapes/'$Image'" class="gallery" alt="'$Title'" /></a><br /><p class="title">'$Title'</p><p class="description">'$Width'” x '$Height'”</p><p class="sold">'$IsItSold'</p></td>';

$column=2;

}

 

elseif ($column == 2)// second column display

{

echo "<td><a href=\"javascript:PopupPic('../images/popups/landscapes/"$BigImage"')\"><img src=\"../images/landscapes/"$Image"\" class=\"gallery\" alt=\""$Title"\" /></a><br />

<p class=\"title\">"$Title"</p>

<p class=\"description\">"$Width"” x "$Height"”</p>

<p class=\"sold\">"$IsItSold"</p>

</td>";

$column=3;

}

 

else// third column display

{

echo "<td><a href=\"javascript:PopupPic('../images/popups/landscapes/"$BigImage"')\"><img src=\"../images/landscapes/"$Image"\" class=\"gallery\" alt=\""$Title"\" /></a><br />

<p class=\"title\">"$Title"</p>

<p class=\"description\">"$Width"” x "$Height"”</p>

<p class=\"sold\">"$IsItSold"</p>

</td></tr>";

$column=1;

}

$count += 1;

}

 

Thanks for any help you can give a newbie.

 

[jeger003]

anytime you echo html you need to change " (double quotes) to ' (single qoute) because echo begins and ends with double quotes............so just change all double qoutes in

 

 

echo "your html";

 

 

to single qoutes and see if that works

[Mchl]

Proper code highlighting...

echo '<tr><td><a href="javascript:PopupPic(\'../images/popups/landscapes/'$BigImage'\')"><img src="../images/landscapes/'$Image'" class="gallery" alt="'$Title'" /></a><br /><p class="title">'$Title'</p><p class="description">'$Width'” x '$Height'”</p><p class="sold">'$IsItSold'</p></td>';

 

and we see our culprits (in blue).

 

To join strings together use concatenation operator (.)

 

echo 'something'.$variable.'something else';

 

You can also use double quotes

 

echo "something $variable something else";

[raytri]

Thanks, mchl. The periods did the trick.

 

Now if I can just get my php variable names to match the field names pulled out of the database....